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klasskru [66]
3 years ago
8

When 15.0 g of zinc metal reacts with excess hcl, how many liters of h2 gas are produced at stp?

Chemistry
1 answer:
tekilochka [14]3 years ago
8 0
M(Zn)=65.4 g/mol
15.0g Zn*1mol Zn/65.4 g Zn = 15/65.4 mol Zn

                               Zn +2HCl--->ZnCl2 + H2
by equation          1 mol                            1 mol
from the problem 15/65.4 mol                15/65.4 mol

Molar volume of any gas under STP = 22.4 L/mol

 15/65.4 mol H2 * 22.4 L/1 mol= 5.14 L H2


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What volume of o2 is needed to react fully with 720. Ml of nh3
Galina-37 [17]

Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.

<h3>What is volume?</h3>

Volume is the area occupied by the substance and is the ratio of the mass to the density.

At STP, 1 mole of gas occupies 22.4 L of volume

Given,

Volume of ammonia reacted = 0.720 L

The combustion reaction is shown as,

\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O

From the stoichiometry of the reaction, it can be said that,

(4 \times  22.4) L of ammonia reacts with (5 \times  22.4) L of oxygen gas.

So, 0.720 L of  ammonia will react with:

\dfrac{ (5 \times  22.4)}{(4 \times  22.4)} \times 0.720 = 0.9 \;\rm L

Therefore, the volume of oxygen required is 900 mL.

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