When 15.0 g of zinc metal reacts with excess hcl, how many liters of h2 gas are produced at stp?

1 answer:

8 0

M(Zn)=65.4 g/mol
15.0g Zn*1mol Zn/65.4 g Zn = 15/65.4 mol Zn

Zn +2HCl--->ZnCl2 + H2
by equation 1 mol 1 mol
from the problem 15/65.4 mol 15/65.4 mol

Molar volume of any gas under STP = 22.4 L/mol

15/65.4 mol H2 * 22.4 L/1 mol= 5.14 L H2

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