Answer:
UV=29
Step-by-step explanation:
In right triangles AQB and AVB,
∠AQB = ∠AVB ...(i) {Right angles}
∠QBA = ∠VBA ...(ii) {Given that they are equal}
We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle
∠AQB+∠QBA+∠BAQ=180 ...(iii)
∠AVB+∠VBA+∠BAV=180 ...(iv)
using (iii) and (iv)
∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV
∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV (using (i) and (ii))
∠BAQ=∠BAV...(v)
Now consider triangles AQB and AVB;
∠BAQ=∠BAV {from (v)}
∠QBA = ∠VBA {from (ii)}
AB=AB {common side}
So using ASA, triangles AQB and AVB are congruent.
We know that corresponding sides of congruent triangles are equal.
Hence
AQ=AV
5x+9=7x+1
9-1=7x-5x
8=2x
divide both sides by 2
4=x
Now plug value of x=4 into UV=7x+1
UV=7*4+1=28+1=29
<u>Hence UV=29 is final answer.</u>
Answer:
E. 35°, 70°
Step-by-step explanation:
Sum of angles add up to 180° in every triangle.
Step 1: Set up equation
a + 2a + 75 = 180
Step 2: Combine like terms
3a + 75 = 180
Step 3: Subtract 75 on both sides
3a = 105
Step 4: Divide both sides by 3
a = 35
So 1 angle is 35°
Step 5: Plug in <em>a</em> to find last angle
2(35) = 70°
Yes because when you turn into a decimal it's 7.2
Answer:
4/5
Step-by-step explanation:
Step-by-step explanation:
- In a right triangle, if ∠B is 45°, then ∠C is too.
-- Since ∠B and ∠C are equal, the sides opposite them
are equal too. This is an isosceles right triangle. Its legs
are equal.
-- (The hypotenuse)² = (one leg)² + (the other leg)²
= (12-ft)² + (12-ft)²
= (144 x 2)
The hypotenuse = √(144 x 2) = 12√2 .
LOL