Answer:
Below, depends if 27 is term number 1 or term number 0. Answered for both cases.
Step-by-step explanation:
The most common sequences are arithmetic and geometric, so lets check those first.
Arithmetic first since its the easiest.
to go from 27 to 21 we subtract 6, if we subtract 6 from 21 again we get to 15, which is what we need, so it is indeed arithmetic.
Explicit formula is basically of the form of y=mx+b with an arithmetic sequence. the m is the common difference and b is the first term minus the common difference. so lets fill those in. y = -6x + 33
Then it usually has n as the x and y f(n) so we'll just put those in
f(n) = -6n + 33
This si as long as the first term is labeled as term number 1 and not term number 0. if you have 27 as term 0 instead just make 33 back to 27, so f(n) = -6n + 27
Let me know if this doesn't make sense.
The answer I believe is c
Can you get a better shot of the problem?
Answer:
"is" (and any subsequent words) was ignored because we limit queries to 32 words.
Answer: the 7th person will get 3.125 pieces of gum.
Step-by-step explanation:
The first student gets one-half and each student gets half of what's left each time. This means that number of pieces of gum that each student gets is reducing in geometric progression. The formula for determining the nth term of a geometric progression is expressed as
Tn = ar^(n - 1)
Where
a represents the first term of the sequence.
r represents the common ratio.
n represents the number of terms.
From the information given,
a = 200
r = 0.5
n = 7
The 7th term, T7 is
T7 = 200 × 0.5^(7 - 1)
T7 = 200 × 0.5^6
T7 = 3.125
