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2 years ago

Please help I am so confused lol. I’ll mark you the brainiest

Mathematics

1 answer:

ANTONII [103]2 years ago

3 0

Answer:

Since the pentagon is regular, the line connecting the centre of the circle to the verticles (A,B,C,D,E) should inscribe an equal angle in them

You can see what I mean in the attachment

So to mark other points we follow the following steps

Connect OA
With OA as base, make angle of 72°. Say th new line is OB.
Similarly, do for the rest of them
This is a cyclic pentagon

Step-by-step explanation:

Hope this helps... Pls vote as brainliest

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Tommy finished 3/5 of the race in 6 hour. how long was the entire race?

lesya692 [45]

Hello there,

Well to find the total time you would have to set up a proportion...

6 / 3/5 = x / 1

Now you crosss multiply and divide...

6 * 1 = 6

6 / 3/5 =30/3 = 10

Answer: 10 hours

Hope I helped!!

-Char

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2 years ago

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3 years ago

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shtirl [24]

Answer:

Step-by-step explanation:

The slope of the line in question is the same as the slope of the line parallel to it. Using y = mx + b, where m is the slope, we find the slope of our line is -3.

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2 years ago

I need to find the slope, x intercept and y intercept please help

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2 years ago

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

2 years ago