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atroni [7]
3 years ago
6

Someone please help me

Mathematics
2 answers:
Vanyuwa [196]3 years ago
8 0

Answer: C

Step-by-step explanation:

LM is half of BC

LN is half of AC

Angles in a triangle add up to 180 degrees

90+35+x= 180

125+x=180

180-125=55

C 55 degrees

No matter side length, angles will be the same

nadezda [96]3 years ago
3 0

Answer:

55 degrees

Step-by-step explanation:

Even though they are different sizes, when triangles are similar, they have the same angle measures. Since angle A corresponds to angle N, they have the same angle measure. The measure of angle N is given as 55 degrees, so angle A has the same measure.  

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Which relation is a function ?
Leokris [45]

Answer:

Bottom left

Step-by-step explanation:

If you can draw a vertical line through a graph and touch only one point, the relation is a function.

3 0
4 years ago
The quadrilateral ABCD has area of 58 in2 and diagonal AC = 14.5 in. Find the length of diagonal BD if AC ⊥ BD.
azamat

Answer:

(look in the the Step by step)

Step-by-step explanation:

When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.

.. A = (1/2)*d₁*d₂

Substituting the given information, this becomes

.. 58 in² = (1/2)*(14.5 in)*d₂

.. 2*58/14.5 in = d₂ = 8 in

The length of diagonal BD is 8 in.

4 0
3 years ago
Need help number 2 for a quiz !!!
Svetach [21]

Answer: radius: 6, center: (3,-4)

Step-by-step explanation:

5 0
3 years ago
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Please help!!!!!! + lots of points
Ilya [14]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~

The correct answers are A, B, D, and E

4 0
3 years ago
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Quadrilateral KLMN has vertices of K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4) Find the length of MN
Olenka [21]

Answer:

The length of MN is \sqrt{5} units.

Step-by-step explanation:

The given Quadrilateral KLMN has vertices at K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4).

We use the distance formula to find the length of MN.

|MN|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We plug in the values to get

|MN|=\sqrt{(-4--2)^2+(-4--5)^2}

|MN|=\sqrt{(-2)^2+(1)^2}

|MN|=\sqrt{4+1}

|MN|=\sqrt{5}

The length of MN is \sqrt{5} units.

3 0
4 years ago
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