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3 years ago

Quotient of 8 decreased by 2 times t and 3

Mathematics

1 answer:

Paraphin [41]3 years ago

4 0

Answer:

$Quotient = \frac{8 - 2t}{3}$

Step-by-step explanation:

Quotient, in maths, is what you get when two number or expressions together. That is, dividend over the divisor.

Thus, from what we're given:

dividend is 8 decreased by 2 times t, which can be expressed as $8 - 2*t = 8 - 2t$ .

The divisor is 3.

$Quotient = \frac{8 - 2t}{3}$

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A recipe calls for 4 cups of sugar to 5 cups of flour. How many cup(s) of

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Answer:

4/9

Step-by-step explanation:

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3 years ago

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Segment wx is shown Explain how you would construct a perpendicular bisector of wx using a compass and a straightedge

n200080 [17]

Answer:

To perpendicular bisector of line segment WX. There are following steps:

1) Draw arcs or circles from points A and B on the both sides of WX.

2) Name the intersection points as W and X.

3) Use the straightedge to draw a line through points W and X.

4) Name the point as O

hence we have construct perpendicular bisector AB of WX which bisects at O.

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3 years ago

I need help To find gradient and y-intercept...

suter [353]

Answer:

a) the gradient of the linear graph is: $\mathbf{\frac{-1}{3} }$

b) the y-intercept of linear graph is -1

Step-by-step explanation:

a) Find the gradient of the linear graph.

The formula used to find gradient is same as slope

$Gradient=\frac{Change \ in \ y \ coordinate}{Change \ in \ x \ coordinate}\\or\\Gradient=\frac{y_2-y_1}{x_2-x_1}$

Take any 2 points from the graph.

I will take: (-3,0) and (0,-1)

Putting values in formula and finding gradient

$Gradient=\frac{y_2-y_1}{x_2-x_1} \\Gradient=\frac{-1-0}{0-(-3)} \\Gradient=\frac{-1}{3}$

So, the gradient of the linear graph is: $\mathbf{\frac{-1}{3} }$

b) Find the y-intercept of linear graph

The y-intercept of linear graph is the value of y at the point where the line crosses the y axis.

So, in the given graph, that point is -1

So, the y-intercept of linear graph is -1

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3 years ago

Rhonda had a piece of ribbon that was 5 feet 3 inches long. She removed a 5-inch piece to use in her art project. What is the le

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Answer:

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4 years ago

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Reflection Over Parallel Lines Please complete the attached reflection. Thanks!

Allushta [10]

Answer: A(3, -5)

B(6, -2)

C(9, -2)

Step-by-step explanation:

If we have a point (x, y), and we do a reflection over the axis y = a, then the only thing that will change in our point is the value of x.

Now, the distance between x and a must remain constant before and after the reflection.

so if x - a = d

then the new position of the point will be:

(a - d, y) = (2a - x, y).

I will use that relationship for the 3 points

We start with the point (1, -5)

The reflection over y = -1 leaves.

The distance between 1 and -1 is = 1 - (-1) = 2.

Then the new point is (-1 - 2, -5) = (-3, -5)

Now we do a reflection over y = 1, so D = -3 - 1 = -2

Then the new point is:

A = (1 -(-2), -5) = (3, -5)

B) (2, -2)

Reflection over y = -1.

distance, d = 2 - (-1) = 3

the point is (-1 - 3, -2) = (-4, -2)

Now, a reflection over y = 1.

The distance is D = -4 - 1 = -5

The new point is (1 - (-5), 2) = (6, -2)

C) (5, -2)

reflection over y = -1

Distance: D = 5 - ( - 1) = 6

New point: (-1 - 6, -2) = (-7, -2)

Reflection over y = 1.

Distance D = -7 - 1 = -8

New point ( 1 - (-8), -2) = (9, -2)

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3 years ago