The domain that is an onion is the <span>Eukaryote.
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Answer:
ph = 4.73
Explanation:
Determine the pH of a 0.62 M NH4NO3 solution at 25C
The Kb for NH3 is 1.76 x 10^-5
NH4+ is the conjugate acid of the base NH3
Ka for NH4+ = K water / K NH3 conjugate base
Ka = 1 × 10⁻¹⁴ / 1.76 10⁻⁵
= 5.68 × 10⁻¹⁰
which is he Ka for
NH4 + H2O --> NH4OH + H⁺
Ka = [NH4OH] [H+] / [NH4)+]
5.68 × 10⁻¹⁰ = [X] [X] / [0.62]
X² = 3.52 × 10⁻¹⁰
X = [H+] = 1.88 × 10⁻⁵
p of that H+ = 4.73
ph = 4.73
Answer:
Explanation:
1. Select all the statements about the nucleus of the atom that are correct:
Group of answer choices
B. It contains Protons
D. It has a Positive Charge
E. It contains Neutrons
2. An atom of an element with atomic number 50 and mass number 120 contains:
Group of answer choices
B. 50 protons, 50 electrons, and 70 neutrons
3. Which of these statements is false?
Group of answer choices
D. Electrons have the same mass as a proton but have the opposite charge.
Answer:
18 g
Explanation:
Step 1: Write the balanced equation
2 Al + 6 HCl ⇒ 2 AlCl₃ + 3 H₂
Step 2: Calculate the moles of Al
The molar mass of Al is 26.98 g/mol.
28.1 g × 1 mol/26.98 g = 1.04 mol
Step 3: Calculate the moles of HCl
46 mL of 1 M HCl react.
0.046 L × 1 mol/L = 0.046 mol
Step 4: Determine the limiting reactant
The theoretical molar ratio of Al to HCl is 2:6 = 0.33:1.
The real molar ratio of Al to HCl is 1.04:0.046 = 22.6:1
According to this, the limiting reactant is HCl.
Step 5: Calculate the mass of AlCl₃ generated from 0.046 moles of HCl
The molar ratio of HCl to AlCl₃ is 6:2. The molar mass of AlCl₃ is 133.34 g/mol.
0.046 mol HCl × 6 mol HCl/2 mol AlCl₃ × 133.34 g AlCl₃/1 mol AlCl₃ = 18 g AlCl₃