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4 years ago

9

I13 babies are born to every 1000 person each year.If the population was 58,400,000 in 2000 , how many babies were born that yea

r?

1 answer:

alina1380 [7]4 years ago

7 0

Number of babies=(58,400,000/1,000)*113=58,400*113=?

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(5CQ) Use the comparison test to determine whether the series 25/3+125/9+625/27+... is convergent or divergent.

olya-2409 [2.1K]

The terms in the sum are given by the sequence

$\left\{\dfrac{5^{n+1}}{3^n}\right\}_{n\ge1}$

We have

$\dfrac{5^{n+1}}{3^n}>\dfrac{5^n}{3^n}=\left(\dfrac53\right)^n>1$

for all $n$ , and the series $1+1+1+\cdots$ clearly diverges, so $\dfrac{25}3+\dfrac{125}9+\cdots$ must also diverge.

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3 years ago

L33. Solve 41x - 7 + 12 = 28<br> Solution(s).

s2008m [1.1K]

Answer:

41x-7+12=28

41x+5=28

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3 years ago

A bag of marbles has 3 red, 4 blue, and 5 white marbles in it. What is the probability of reaching in and selecting a blue marbl

goblinko [34]

Answer:

$P(B)=\frac{1}{3}$

Step-by-step explanation:

The number of red marbles in the bag is; $n(R)=3$ .

The number of blue marbles in the bag is; $n(B)=4$ .

The number of white marbles in the bag is; $n(W)=5$ .

The total number of marbles in the bag is: $n(S)=3+4+5=12$ .

The probability of selecting a blue marble is $P(B)=\frac{n(B)}{n(S)}$

We substitute the given information to obtain:

$P(B)=\frac{4}{12}$

We simplify to obtain:

$P(B)=\frac{1}{3}$

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3 years ago

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kolbaska11 [484]

Answer:

let common difference be d.

a 18=a+17 d

a 14=a+13 d

a+17d - (a+13d) =32

a+17d - a - 13d =32

17d - 13d = 32

4d = 32

d=32/4

d=8

common difference=8

Step-by-step explanation:

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Answer:

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3 years ago