Find the area of the parallelogram with vertices k(1, 2, 2), l(1, 5, 3), m(3, 11, 3), and n(3, 8, 2).
Reil [10]
On examining the sides of the parallelogram, we see that the side KL lies in the plane x=1, and the side MN lies in the plane x=3.
Hence the height of the parallelogram is h=(3-1)=2.
The length of side mKL=sqrt((5-2)^2+(3-2)^2)=sqrt(3^2+1^2)=sqrt(10)
The length of side mMN=sqrt((11-8)^2+(3-2)^2)=sqrt(3^2+1^2)=sqrt(10)
Therefore the area of the parallelogram is mKL*h = sqrt(10)*2 = 2sqrt(10)
Answer: Area of parallelogram =
Slope: (y2-y1)/(x2-x1) = m
Find the slope, m, then pick a point, plug in the x, y, and m, and solve for b in the equation:
y = mx + b
That is your y-intercept.
Take out your x and y, plug in m and b, and that is your generic form for your line, t.
Answer:
4.5
Step-by-step explanation:
36 divided by 8 = 4.5. Maybe you meant 2 dozen, making it 24 divided by 8 = 3
Answer:
y=x3−7x2+2x+4
Step-by-step explanation: