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nexus9112 [7]
3 years ago
15

1.875mps into kilometers per hour​

Chemistry
1 answer:
worty [1.4K]3 years ago
6 0

Answer:

6,75 kilometres per hour

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If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
irinina [24]

Answer:

4.13 g

Explanation:

Data Given:

Amount of CO₂ Produced = 15 g

Amount of Oxygen = 11 g

Amount of Carbon used = ?

Solution:

Suppose Carbon dioxide (CO₂) is formed by the reaction of carbon and oxygen then the reaction will be as below

                            C   +   O₂    -------------> CO₂

                          1 mol    1 mol                  1 mol

we come to know from the above reaction that

1 mole of carbon react with 1 mole of oxygen to produce 1 mol of carbon dioxide.

molar mass of C = 12 g/mol

molar mass of O₂ = 32 g/mol

molar mass of CO₂ = 12 + 2(16) = 44 g/mol

if we represent mole in grams then

           C               +                        O₂                     ------------->        CO                 1 mol (12 g/mol)                      1 mol (32 g/mol)                      1 mol (44 g/mol)

                   

              C   +   O₂    -------------> CO₂

            12 g       32 g                   44 g

So,

we come to know that 32 g of Oxygen combine with 12 g  of oxygen produce 44 g CO₂

So now how much of Carbon will be combine with 11 g of oxygen

apply unity formula

                32 g of  O₂ ≅ 12 g of  C

                  11 g of O₂  ≅  g of  C

by doing cross multiplication

           g of C = 12 g x 11 g / 32 g

           g of C = 132 g / 32 g

           g of C = 4.13 g

So,

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

to check this answer

we use the above information

                     12 g of  C ≅ 44 g of CO₂

                     4.13 g of C ≅  g of  CO₂

by doing cross multiplication

                    g of  CO₂ = 44 g x 4.13 g / 12 g

                    g of CO₂ = 15g

So it is confirmed that

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

4 0
3 years ago
An ionic compound is composed of the following elements:
Amiraneli [1.4K]

Answer: N3 H12 P O3

Explanation:

From the question :

N = 31.57% H = 9.10% P = 23.27%

O= 36.06%

Divide each of the element by their respective relative atomic masses.

N = 31.57 / 14 = 2.26

H = 9.10/ 1 = 9.10

P = 23.27 / 31= 0.750

O =36.06 / 16 = 2.25

Divide each answer by the lowest of them all, we then have:

N = 2.26/ 0.750 = Approx = 3

H = 9.10 / 0.750 = Approx = 12

P = 0.750/ 0.750= 1

O = 2.25 / 0.750 = Approx = 3

The empiral formula is

N3 H12 P O3

6 0
3 years ago
Read 2 more answers
On a camping trip, Marta roasts a marshmallow in the campfire. The marshmallow grows, and then turns black.
Mandarinka [93]

Answer:

The answer is D.

Explanation:

4 0
3 years ago
Read 2 more answers
When energy is added to solid manganese(ii) sulfate heptahydrate crystals they break down to form liquid water and solid mangane
RoseWind [281]
Chemical reaction: MnSO₄·7H₂O → MnSO₄·H₂O + 6H₂O.
MnSO₄·7H₂O is <span>manganese(II) sulfate heptahydrate.
</span>MnSO₄·H₂O is <span>manganese(II) sulfate monohydrate.
Manganese has oxidation number +2 and sulfate anion has oxidation number -2. For </span><span>crystallization water h</span>epta means seven and mono means one.
7 0
3 years ago
Consider the reaction zn + no− 3 → nh3 + zn(oh)2− 4 carried out in an aqueous basic solution. when the equation is properly bala
Inessa05 [86]
Balancing the reaction is done to obey the law of nature, particularly, the Law of Definite Proportions. The concept is, the amount of the same element before and after the reaction must be the same. This is actually a redox reaction.

Oxidation half-reaction: Zn  + 4 OH⁻ → Zn(OH)₄²⁻ + 2 e-  

Reduction half-reaction: NO₃⁻ + 6 H₂O + 8 e-→ NH₃ + 9 OH⁻

Adding both reaction, we get the overall complete balanced equation:

<span>4Zn + NO</span>₃⁻ + 6 H₂O + 7 OH⁻  → 4 Zn(OH)₄²⁻ + NH₃

Thus, the charge in the product side is 4*-2 = <em>-8</em>.

3 0
3 years ago
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