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Lena [83]
3 years ago
7

Solid aluminum (AI) and oxygen (O_2) gas react to form solid aluminum oxide (Al_2O_3). Suppose you have 7.0 mol of Al and 9.0 mo

l of O_2 of in a reactor. Calculate the largest amount of Al_2O_3 that could be produced. Round your answer to the nearest 0.1 mol. .
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

Explanation:

Step 1: Data given

Numbers of Al = 7.0 mol

Numbers of mol O2 = O2

Molar mass of Al = 26.98 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

4Al(s) + 3O2(g) → 2Al2O3(s)  

Step 3: Calculate limiting reactant

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

Al is the limiting reactant, it will be consumed completely (7 moles).

O2 is in excess.  There will react 3/4 * 7 = 5.25 moles

There will remain 9-5.25 = 3.75 moles

Step 4: Calculate moles Al2O3

For 4 moles Al we'll have 2moles Al2O3

For 7.0 moles of Al we'll have 3.5 moles of Al2O3 produced

Step 5: Calculate mass of Al2O3

Mass Al2O3 = moles Al2O3 * molar mass Al2O3

Mass Al2O3 = 3.5 moles* 101.96 g/mol

Mass Al2O3 = 356.9 grams

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

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Answer:

6.022 x 10²³

Explanation:

The number of atoms =  the number of moles x with the Avogadro's number.

(The Avogadro's number is 6.022 x 10²³ atoms / moles)

number of atoms = 1.00 moles x 6.022 x 10²³ atoms / mole

number of atoms =  6.022 x 10²³ atoms

(There is no need to simplify?) = 6.022 x 10²³

(ps. This is my first time doing this question so im sorry if i got it wrong

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Answer:

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3 years ago
The Bay of Fundy in Nova Scotia, Canada is reported to have the largest tides in the world with high tide and low tide occurring
topjm [15]

The rate in m/s is 5.2 * 10^-4 m/s.

<h3>What is the rate in m/s?</h3>

We know that the speed is given as the ratio of the distance covered to the time taken. In this case, we have been told that the rate at which the tide rises is 6.08 ft per hour. We would now need to convert the rate from  6.08 ft per hour to m/s.

Now;

We know that;

1 foot/hour = 8.5 * 10^-5 m/s

6.08 ft per hour = 6.08 ft per hour * 8.5 * 10^-5 m/s/1 foot/hour

= 5.2 * 10^-4 m/s

Learn more about speed:brainly.com/question/28224010

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