Answer:
A.
Explanation:
I forgot butt im surely it is;-)
PH=14-pOH
pOH=-lg[OH⁻]
pH=14+lg[OH⁻]
pH=14+lg(8.7*10⁻¹²)=14-11.06=2,94
NaOH is a strong base so pH will be around 13 to 12. Whatever number of moles of NaOH you have approximately the pH of NaOH will be around 14 13 or 12
Yes, Benzylamine is miscible, meaning it is soluble at all amounts.