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2 years ago

Do you espect LiF or LiCL to have a higher melting points?

Chemistry

1 answer:

zimovet [89]2 years ago

8 0

Answer:

LiF has the highest melting point.

Reason: If we compare the bond length of the molecules we find that LiF has the shortest bond length due to the fact that F is smallest out of F, Cl, Br, I. As the bond is very short the bond is stronger and hence we need to provide much more energy to break the bond. Hence a higher boiling point.

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When the first ball in a Newton's cradle is pulled back and released, it causes the final ball to move. What does this example o

bazaltina [42]

Answer:

Explanation:

Mechanical energy is energy in motion is the example of mechanical energy⚡

7 0

2 years ago

a gas has a volume of 350 cubic centimeters at 740 mmHg. how many cubic centimeters will the gas occupy at a pressure of 900 mmH

Harrizon [31]

Answer: 287.8 cm3

Explanation:

Given that:

Initial volume of gas V1 = 350 cm3

Initial pressure of gas P1 = 740 mmHg

New volume V2 = ?

New pressure P2 = 900 mmHg

Since, pressure and volume are involved while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

740 mmHg x 350 cm3 = 900mmHg x V2

V2 = (740 mmHg x 350 cm3) /900mmHg

V2 = 259000 mmHg cm3 / 900mmHg

V2 = 287.8 cm3

Thus, the gas will occupy 287.8 cubic centimeters at the new pressure.

3 0

2 years ago

QUESTION 3 (a) Ammonium sulphate, (NH),50, is a soluble salt and it is used in agriculture as fertiliser. 5 g of ammonium sulpha

nataly862011 [7]

Answer:

The equation: (NH₄)₂SO₄ = 2NH4(+) + SO4(-2)

The number of moles = 5 g / 132.14 g/mol = 0.038 mol

The number of molecules = 0.038 X 6.022x10^23 = 2.29x10^23

the number of positive ions present in the ammonium sulphate solution:

2 positive ions for every 1 molecule of (NH₄)₂SO₄

so 2 x 2.29x10^23 = 4.58x10^23

the number of negative ions present in the ammonium sulphate solution

1 negative ion for every 1 molecule of (NH₄)₂SO₄

so 1 x 2.29x10^23 = 2.29x10^23

the total number of ions present in the ammonium sulphate solution

4.58x10^23 + 2.29x10^23 = 6.87x10^23

4 0

2 years ago

A buffer is prepared by adding 12.0g of ammonium chloride (NH4Cl) to 250mL of 1.00 M NH3 solution?The pH is 9.3 Write the net io

solniwko [45]

Answer:- $NH_3(aq)+H^+(aq)\rightleftharpoons NH_4^+(aq)$

Explanations:- The solution we have is a buffer solution and we know that a buffer solution resists a change in its pH if a strong acid or base is added to it.

Here, the buffer solution we have is of a weak base and it's conjugate acid. So, a strong acid(nitric acid) is added to this buffer then it reacts with the base present in the buffer so that the acid could be neutralized. This is called buffer action.

The net ionic equation is written as:

$NH_3(aq)+H^+(aq)\rightleftharpoons NH_4^+(aq)$

Note that $HNO_3$ is a strong acid and nitrate ion is the spectator ion so it is not included in the net ionic equation.