Considering the relation built the presence of point M on line LN, the numerical length of LN is of 9 units.
<h3>What is the relation from the presence of point M on the line LN?</h3>
Point M splits line LN into two parts, LM and MN, hence the total length is given by:
LN = LM + MN.
From the given data, we have that:
Hence we first solve for x.
LN = LM + MN.
2x - 5 = 3 + x - 1
x = 7.
Hence the total length is:
LN = 2x - 5 = 2 x 7 - 5 = 14 - 5 = 9 units.
More can be learned about relations and lines at brainly.com/question/2306122
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3.62p+3.09=18.69
-3.09 -3.09
——————————-
3.62p = 15.60
15.60/3.62
P= 4.31
She can by 4.31 pounds
Answer:
Step-by-step explanation:
5. a) ∠1 and ∠2 are remote interior angles of ∠ACD so that means that ∠ACD = ∠1 + ∠2
b) Because an exterior angle is the sum of its two remote interior angles it makes sense that an exterior angle is greater in measure than either of its remote interior angles.
6. BD = DB Reflexive property
∠3 = ∠5, ∠4 = ∠6 Alt. int. angles
ΔADB = ΔCDB ASA
7. AB = BC Def. of midpoint
∠1 = ∠2 Given
∠BAE = ∠CBD Corresponding angles
ΔBAE = ΔCBD ASA
∠D = ∠E CPCTC
<span>ABC IS AN ANGLE FORMED BY A TANGENT AND CHORD WITH AN INTERCEPTED MINOR ARC FROM A TO B. WHEN TWO CHORDS INTERSECT INSIDE A CIRCLE, FOUR ANGLES ARE FORMED. AT THE POINT OF INTERSECTION, TWO SETS OF CONGRUENT VERTICAL ANGLES ARE FORMED IN THE CORNERS OF THE X THAT APPEARS.</span>
That's correct but whats your question?