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3 years ago

The centripetal force acting on the moon continuously changes the ____________________ of the moon’s motion.

Physics

2 answers:

svlad2 [7]3 years ago

8 0

Changes the direction of the moons motion.

Hatshy [7]3 years ago

7 0

Answer:

The centripetal force acting on the moon continuously changes the <u>Direction of Motion</u> of the moon’s motion.

Explanation:

As we know that the gravitational force of Earth on moon is towards the center of Earth and it is always perpendicular to the direction of velocity of moon

Since the force is always perpendicular to the velocity so it can neither increase the magnitude of the speed nor it can decrease the magnitude.

So here we can say the speed will remain same due to the force of the earth on moon .

Hence this force of earth will only change the direction of the motion of moon during its motion around the Earth.

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The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by which balanced chemical equation?

Strike441 [17]

Answer:

Option B. N2(g) + 3H2(g) → 2NH3(g)

Explanation:

When nitrogen react with hydrogen, they form a product as shown below:

N2+ H2 → NH3

We need to balance the equation. This is illustrated below:

There are 2 atoms of nitrogen on the left side and 1 atom on the right side. To balance it, put 2 in front of NH3 as shown below:

N2+ H2 → 2NH3

Now, There are a total of 6 atoms of Hydrogen on the right side and 2 atoms on the left side side. This can be balanced by putting 3 in front of H2 as shown below:

N2+ 3H2 → 2NH3

Now we see clearly that the equation is balanced as we have equal numbers of atoms of N and H on both sides of the equation

4 0

3 years ago

Read 2 more answers

3 + 2 ∙ 4 = 3 + (2 ∙ 4)

Rzqust [24]

Answer:

11 = 11

Explanation:

6 0

3 years ago

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A particle moves along the x axis. It is initially at the position 0.270 m, moving with velocity 0.140 m/s and acceleration 20.3

mixas84 [53]

Answer:

a) -2.34 m

b) -1.3 m/s

c) 0.056 m

d) 0.320 m/s

Explanation:

part a

Given:

s(0) = 0.27 m

v(0) = 0.14 m/s

a = -0.320 m/s^2

t = 4.50s

Using kinematic equation of motion for constant acceleration:

s (t) = s(0) + v(0)*t + 0.5*a*t^2

s ( 4.5 s ) = 0.27 + 0.14*4.5 + 0.5*-0.32*4.5^2

s(4.5) = -2.34 m

part b

Using kinematic equation of motion for constant acceleration:

v(t) = v(0) + a*t

v(4.5s) = (0.14) + (-0.32)(4.5) = -1.3 m/s

part c

Use equation for simple harmonic motion:

s(t) = A*cos(w*t)

v(t) = -A*w*sin (w*t)

a(t) = -A*(w)^2 * cos (w*t)

0.27 m = A*cos(w*t) .... Eq 1

0.14 m/s = - A*w*sin (w*t) .....Eq2

-0.320 = -A*(w)^2 * cos (w*t) .... Eq3

Solve the three equations above for A, w, and t

Divide 1 and 3:

w^2 = 0.32 / 0.27

w = 1.0887 rad / s

Divide 2 and 1:

w*tan(wt) = 0.14 / 0.27

tan(1.0887*t) = 0.476289

t = 0.4083 s

A = 0.27 / cos (1.0887*0.4083) = 0.3 m

Hence, the SHM is s(t) = 0.3*cos(1.0887*t)

s(4.5) = 0.3*cos(1.0887*4.5) = 0.056 m

part d

v(t) = - 0.32661 * sin (1.0887*t)

v(4.5) = - 0.32661 * sin (1.0887*4.5) = 0.320 m/s

3 0

3 years ago

PERSONAL QUESTION <br> if a bird can fly why can't a fly just bird ?

Sergeeva-Olga [200]

Answer:

counter question if you get out the shower clean then how does your towel get dirty?

3 0

4 years ago

Read 2 more answers

What is the magnitude of the minimum magnetic field that will keep the particle moving in the earth's gravitational field in the

Zepler [3.9K]

Answer:

The magnitude of the magnetic field vector is 1.91T and is directed towards the east.

The steps to the solution can be found in the attachment below.

Explanation:

For the charge to remain in the the earth' gravitational field the magnetic force on the charge must be equal to the earth's gravitational force on the charge and must act opposite the direction of the earth's gravitational force.

Fm = Fg

qvBSin(theta) = mg

Where q = magnitude of charge

v = magnitude of the velocity vector = 4 x10^4 m/s

B = magnitude of the magnetic field vector

theta = the angle between the magnetic field and velocity vectors = 90°

m = mass of the charge = 0.195g

g = acceleration due to gravity =9.8m/s²

On substituting the respective values of all variables in the equation (1) above

B = 1.91T

The direction of the magnetic field vector was found by the application of the right hand rule: if the thumb is pointed in the direction of the magnetic force and the index finger is pointed in the direction of the velocity vector, the middle finger points in the direction of the magnetic field.

Below is the step by step procedure to the solution.

3 0

3 years ago