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Scilla [17]
3 years ago
12

3 + 2 ∙ 4 = 3 + (2 ∙ 4)

Physics
2 answers:
Rzqust [24]3 years ago
6 0

Answer:

11 = 11

Explanation:

AnnZ [28]3 years ago
6 0

Answer:

True

Explanation:

3+2x4=3+(2x4), they both equal 11

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PLEASE HELP WILL GIVE BRANIST IT WOULD REALLY BE APPRICATIED
Natasha_Volkova [10]

Answer:

solids are strong and compact, they are not compressable.

liquids are flexible and less compacts they can not be coompresed

4 0
2 years ago
A small metallic bob is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizonta
shusha [124]

Answer:

19.99 kg m²/s

Explanation:

Angular Momentum (L) is defined as the product of the moment of Inertia (I) and angular velocity (w)

L = m r × v.

r and  v are perpendicular to each other,

where r = lsinθ.

l = 2.4 m

θ= 34°

g = 9.8 m/s²  and m = 5 kg

resolving using newtons second law in the vertical and horizontal components.

T cos θ − m g = 0

T sin θ − mw² lsin θ = 0

where T is the force with which the wire acts on the bob

w = √g / lcosθ

= √ 9.8 / 2.4 ×cos 34

= 2.2193 rad/s

the angular momentum  L = mr× v

= mw (lsin θ)²

= 5 × 2.2193 (2.4 ×sin 34°)²

=19.99 kg m²/s

8 0
3 years ago
A soccer ball is kicked At 8m/s. It lands on the ground after being in the air for .85 seconds. At what angle is it kicked?
SpyIntel [72]

If ball remains in air for total time T = 0.85 s

this is also known as time of flight

In order to find the time of flight we can use kinematics

\Delta Y = v_y*t + \frac{1}{2}at^2

so for complete motion its displacement in y direction will be zero

0 = v_y* 0.85 + \frac{1}{2}(-9.8)(0.85^2)

0 = v_y*0.85 - 3.54

v_y = 4.165 m/s

now we know that net velocity of the ball is 8 m/s

while is y direction component we got is vy = 4.165 m/s

now by component method we can say

v_y = v sin\theta

4.165 = 8 sin\theta

\theta = sin^{-1}\frac{4.165}{8}

\theta = 31.4^0

so it is projected at an angle of 31.4 degree above horizontal

8 0
3 years ago
Starting from rest, a boat increases its speed to 4.12 m/s with constant acceleration. (a)
Gemiola [76]

Answer:

initial velocity = 0 m/s

final velocity = 4.92 m/s

constant acceleration so,

(a) average velocity =

(initial velocity + final velocity)/2

(b) distance = average velocity x time

substitute and calculate

Explanation:

HOOE ITS HELP ;)

7 0
2 years ago
Consider 2 converging lenses of focal lengths 5 mm (objective) and 50 mm.(eyepiece) An object 0.1 mm in size is placed a distanc
AleksandrR [38]

Answer:

1)   q₁ = 12.987 cm , b)       L = 17.987 cm , c)      m = 179.87

Explanation:

We can solve the geometric optics exercises with the equation of the constructor

         1 / f = 1 / p + 1 / q

where f is the focal length, p and q are the distance to the object and the image respectively.

Let's apply this equation to our case

1) f = 5mm = 0.5 cm

    p₁ = 5.2 mm = 0.52 cm

    h = 0.1 mm = 0.01 cm

    1 / q₁ = 1 / f- 1 / p

    1 / q₁ = 1 / 0.5 - 1 / 0.52 = 2 - 1.923

    1 / q₁ = 0.077

    q₁ = 12.987 cm

2) in this part they tell us that the eyepiece creates an image at infinity, therefore the object that comes from being at the focal length of the eyepiece

            p₂ = 5 cm

The absolute thing that goes through the two lenses is

           L = q₁ + p₂

           L = 12.987 +5

           L = 17.987 cm

3) This lens configuration forms the so-called microscope, whose expression for the magnifications

           m = -L / f_target 25 cm / f_ocular

           m = - 17.987 / 0.5 25 / 5.0

            m = 179.87

8 0
3 years ago
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