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3 years ago

Difference between incident ray and reflected ray

Physics

1 answer:

SSSSS [86.1K]3 years ago

3 0

Answer:

An incident ray is a ray of light that strikes a surface. The angle between this ray and the perpendicular or normal to the surface is the angle of incidence.

The reflected ray corresponding to a given incident ray, is the ray that represents the light reflected by the surface. The angle between the surface normal and the reflected ray is known as the angle of reflection. The Law of Reflection says that for a specular (non-scattering) surface, the angle of reflection always equals the angle of incidence.

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Answer:

0.631 m

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Explanation:

m = Mass = 2.47 kg

v = Velocity = 2.30 m/s

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In this system the energy is conserved

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An engineering intern is studying the effect of temperature on the resistance of a current carrying wire. She applies a voltage

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Answer:

I=2.80 A

Explanation:

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I=V/R=V/(R₀ (1.1599)

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R=R₀ (1+3.9*10⁻³ *(-88-20))

R=R₀ (0.5788)

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3 years ago

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3 years ago

Assuming typical speeds of 8.5 km/s and 5.5 km/s for P and S waves, respectively, how far away did the earthquake occur if a par

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Answer:

The earthquake occurred at a distance of 1122 km

Explanation:

Given;

speed of the P wave, v₁ = 8.5 km/s

speed of the S wave, v₂ = 5.5 km/s

The distance traveled by both waves is the same and it is given as;

Δx = v₁t₁ = v₂t₂

let the time taken by the wave with greater speed = t₁

then, the time taken by the wave with smaller speed, t₂ = t₁ + 1.2 min, since it is slower.

v₁t₁ = v₂t₂

v₁t₁ = v₂(t₁ + 1.2 min)

v₁t₁ = v₂(t₁ + 72 s)

v₁t₁ = v₂t₁ + 72v₂

v₁t₁ - v₂t₁ = 72v₂

t₁(v₁ - v₂) = 72v₂

$t_1 = \frac{72v_2}{v_1-v_2}\\\\t_1 = \frac{72*5.5}{8.5-5.5}\\\\t_1 = 132 \ s$

The distance traveled is given by;

Δx = v₁t₁

Δx = (8.5)(132)

Δx = 1122 km

Therefore, the earthquake occurred at a distance of 1122 km

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3 years ago

Difference between incident ray and reflected ray​

Difference between incident ray and reflected ray