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allsm [11]
2 years ago
14

Assuming typical speeds of 8.5 km/s and 5.5 km/s for P and S waves, respectively, how far away did the earthquake occur if a par

ticular seismic station detects the arrival of these two types of waves 1.2 min apart
Physics
1 answer:
taurus [48]2 years ago
4 0

Answer:

The earthquake occurred at a distance of 1122 km

Explanation:

Given;

speed of the P wave, v₁ = 8.5 km/s

speed of the S wave, v₂ =  5.5 km/s

The distance traveled by both waves is the same and it is given as;

Δx = v₁t₁ = v₂t₂

let the time taken by the wave with greater speed = t₁

then, the time taken by the wave with smaller speed, t₂ = t₁ + 1.2 min, since it is slower.

v₁t₁ = v₂t₂

v₁t₁ = v₂(t₁ + 1.2 min)

v₁t₁ = v₂(t₁ + 72 s)

v₁t₁ = v₂t₁ + 72v₂

v₁t₁ - v₂t₁ = 72v₂

t₁(v₁ - v₂) = 72v₂

t_1 = \frac{72v_2}{v_1-v_2}\\\\t_1 =   \frac{72*5.5}{8.5-5.5}\\\\t_1 = 132 \ s

The distance traveled is given by;

Δx = v₁t₁

Δx = (8.5)(132)

Δx = 1122 km

Therefore, the earthquake occurred at a distance of 1122 km

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2 years ago
Section 1 - Question 30
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Answer : A
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3 0
3 years ago
A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following case
Murljashka [212]

Answer:

The answer is below

Explanation:

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the

cable for the following cases:

a. The load moves downward at a constant velocity

b. The load accelerates downward at a rate 0.4 m/s??

C. The load accelerates upward at a rate 0.4 m/s??

Solution:

Acceleration due to gravity (g) = 10 m/s²

a) Given that the mass of the crane (m) is 140 kg. If the load moves downward, the tension (T) is given by:

mg - T = ma

Since the load has a constant velocity, hence acceleration (a) = 0. Therefore:

mg - T = m(0)

mg - T = 0

T = mg

T = 140(10) = 1400 N

T = 1400 N

b)  If the load moves downward, the tension (T) is given by:

mg - T = ma

T = mg - ma = m(g - a)

T = 140(10 - 0.4) = 140(9.96) = 134.4

T = 134.4 N

c)  If the load moves upward, the tension (T) is given by:

T - mg = ma

T = ma + mg = m(a + g)

T = 140(0.4 + 10) = 140(10.4)

T = 145.6 N

2) To find the distance (s) if the load move from rest (u= 0) and accelerates for 20 seconds (t = 20). We use:

s = ut + (1/2)gt²

s = 0(20) + (1/2)(10)(20)²

s = 2000 m

7 0
3 years ago
Juan lifts a 7.5 kilogram rock 1.75 meters in 5.0 seconds. How much work is done,
ivann1987 [24]

Answer:

The work done W = = 128.63 J

The power, p = 25.7 watts

Explanation:

Given,

The mass of the rock, m = 7.5 kg

The displacement of the rock, s = 1.75 m

The time period of work, t = 5 s

The force acting on the body,

                                  F = m x g

                                     = 7.5 kg x 9.8 m/s²

                                    = 73.5 N

The work done is given by the relation,

                                  W = F x S

Substituting the given values,

                                  W =  73.5 x 1.75

                                      = 128.63 J

The power is defined as the rate of doing work

                                    P = W / t

                                       = 128.63 / 5

                                       = 25.7 watts

Hence, the power, p = 25.7 watts

8 0
3 years ago
Read 2 more answers
PLEASE HELP MEEE You can make a smoothie in a blender with a power of 400 watts and an efficiency of 85 percent. How much energy
telo118 [61]

Answer:

Last option is the correct choice.

Explanation:

Energy = 400\times30\times 0.85

=10200\:J

Best Regards!

5 0
3 years ago
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