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Naily [24]
3 years ago
10

Select the correct answer.

Chemistry
2 answers:
Vlad [161]3 years ago
7 0
A. The temperatures of the iron bars after 30 minutes would be less than 160°C because heat would be lost to the surroundings.
Alecsey [184]3 years ago
6 0

Answer:of

Explanation:

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Why should batteries be stored in the fridge when not being used?
densk [106]

Answer:

because the partieals are cold are pushed away

Explanation:

5 0
3 years ago
Read 2 more answers
Ethanol is used widely as a solvent in laboratories for various chemical reactions. A laboratory technician takes 50.0 mL of eth
puteri [66]
This question is quite vague, as the initial concentration of ethanol is not provided. However, from experience I can tell you that most laboratory work is done with 98% ethanol, and not absolute ethanol (100%). So in order to calculate the final concentration, we need to take the given values, which includes the initial concentration (98%), the initial volume (50.0mL) and the final volume (100.0mL). We apply the following equation to calculate the final concentration:

C1V1 = C2V2
C1 = Initial concentration
C2 = Final concentration
V1 = Initial volume
V2 = Final volume

(98%)(50.0mL) = (C2)(100.0mL)
Therefore, the final concentration (C2) = 49%
8 0
3 years ago
Read 2 more answers
A wave has a frequency of 3,5MHz and a wavelength of 85,5 m. What is the wave velocity through
Yuki888 [10]

Answer:

velocity = 29925×10⁶ m/s

Explanation:

Given data:

Frequency = 35 MHz

Wavelength = 855 m

Velocity = ?

Solution:

MHz to Hz

35×10⁶ Hz

Formula:

<em>velocity = Wavelength × Frequency</em>

velocity = 855 m × 35×10⁶ Hz

velocity = 29925×10⁶ m/s

Hz = s⁻¹

5 0
3 years ago
Realizar un Experimento Teóricamente, considerando la definición de mezcla, dibuja y explicar de forma teórica su proceso de pre
Mrrafil [7]

Answer:

rffdf

Explanation:

7 0
3 years ago
a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte
IgorLugansk [536]

The absorbance reported by the defective instrument was 0.3933.

Absorbance A = - log₁₀ T

Tm = transmittance measured by spectrophotometer

Tm = 0.44

Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654

True absorbance can be calculated by true transmittance, Tm = T+S(α-T)

S = fraction of stray light = 6%= 6/100 = 0.06

α= 1, ideal case

T = true transmittance of the sample

Tm = T+S(α-T)

now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233

therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)

i.e; 0.3933

To know more about transmittance click here:

brainly.com/question/17088180

#SPJ4

3 0
2 years ago
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