Remember pH is defined as: pH = -log[H+]
so, substituting
4 = - log[H+]
-4 = log [H+] Take antilog of both sides
10^(-4) = [H+]
[H+] = 1 x 10^-4 M
We first assume that the gas is ideal which is a safe assumption to approximate the answer to the problem. Then we need to know the ideal gas equation and that is:
PV=nRT
where
P- pressure
V- volume
n-number of moles-
R- ideal gas constant
T-temperature.
Since we know that P, T and V are constant, rearranging the equation would lead to:
P/TR = n/V or the ratio of the moles of gas and volume is constant.
(3moles)/2L = (3+x)/4L
where
x is the additional moles.
Solving for x = 3 moles.
Answer:
11.29Kj
Explanation:
1. find moles of 33.8g of water
Molar mass of H2O: 18.02g/Mol
33.8/18.02= 1.88mols
2. find energy
1.88 x 6.02= 11.29Kj
