The amount of nitrogen oxide in the air sample is determined as 7.01 ppb.
<h3>
Amount of Nitrogen oxide in the air</h3>
The amount of Nitrogen oxide (NO2) in the air in parts per billion (ppb) is calculated as follows;
12 micrograms of NO2 = 12 μg = 12 x 10⁻⁶ g
PV = nRT
V = nRT/P
Where;
- V is volume of NO2 gas
- n is number of moles of NO2 gas
- T is temperature = 40 C = 313 K
n = m/M
M = molar mass of NO2 = 46
n = 12 x 10⁻⁶/46
n = 2.73 x 10⁻⁷ mole
V = (2.73 x 10⁻⁷ x 0.082057 x 313)/(1)
V = 7.01 x 10⁻⁶ L
V = 7.01 x 10⁻⁹ m³
<h3>Amount of NO2 In parts per billion</h3>
= (Volume of NO2)/(volume of air) x 10⁹
= (7.01 x 10⁻⁹)/(1) x 10⁹
= 7.01 ppb
Thus, the amount of nitrogen oxide in the air sample is determined as 7.01 ppb.
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Answer:
first one: how much is reflected
Reason? google search :)
For a liter of a buffer that is 1. 5 m in acetic acid and 0. 70 m in sodium acetate, and with a result in a buffer pH of 4.01, the moles of HCl required is mathematically given as x=0.313mol
<h3>What is the result in a buffer ph of 4. 01?</h3>
Generally, the equation for the pH is mathematically given as
pH=pKa+logsalt/acid
Generally, the equation for the Chemical Reaction is mathematically given as
HCl+CH3CooNa---->NaCl+CH3OOH
Therefore
4.01=4.74+log\frac{0.8-x}{1.3+x}
-0.52=log\frac{0.8-x}{1.3+x}
x=0.313mol
In conclusion, The moles of HCl required is
x=0.313mol
Read more about Chemical Reaction
brainly.com/question/6876669
Answer:
Temperature, heart rate and blood flow.
Explanation:
