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Alexus [3.1K]
3 years ago
13

HELP ON 10 and 11 will mark BRAINLIST

Chemistry
2 answers:
Naddika [18.5K]3 years ago
4 0

Answer:

denity decresses

11: a

Explanation:

brainliest please

Marysya12 [62]3 years ago
4 0
DENITY DECREASE

TELL ME IF YOU NEED TO KNOW WHY
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What is the final volume?
zaharov [31]

Answer:

Option A. 9.4 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 8 L

Initial temperature (T₁) = 293 K

Final temperature (T₂) = 343 K

Final volume (V₂) =?

V₁ / T₁ = V₂ / T₂

8 / 293 = V₂ / 343

Cross multiply

293 × V₂ = 8 × 343

293 × V₂ = 2744

Divide both side by 293

V₂ = 2744 / 293

V₂ = 9.4 L

Therefore, the final volume of the gas is 9.4 L

6 0
3 years ago
Is 3Al + 3FeO → 2Al2O3 + 3Fe a balenced or unbalenced equation?
Murrr4er [49]
3f+5=eo got it right
8 0
3 years ago
What is the solution to the problem expressed to the correct number of significant figures
quester [9]

I don't know what the problem is, but here are some rues to help you out:

  1. All non-zero figures are significant
  2. When a zero falls between non-zero digits, that zero is significant.
  3. When a zero falls after a decimal point, that zero is significant.
  4. When multiplying and dividing significant figures, the answer is limited to the number of sig figs equal to the least number of sig figs in the problem.
  5. When adding and subtracting, the answer is limited to the number of decimal places in the number with the least number of decimal places.
4 0
4 years ago
I'm stuck on this assignment, +20 PTS and BRAINLIEST for step by step:
dolphi86 [110]

Answer:

2. 2.74 L

3. 488 K

4. 7.47 L

5. 38.6 L

6. 2.85 mol

7. 319 K

8. 3.43 kPa

Explanation:

Generally speaking, you want to convert units to SI units, but in this case, we are working with ratios.  This makes up for using the units that wouldn't appropriate elsewhere.

2.  Use the equation P₁V₁ = P₂V₂.  Solve for V₂.  

(3.05 L)(870 kPa) = (969 kPa)(V₂)  

V₂ = 2.74 L.  

3.  Use the equation V₁/T₁ = V₂/T₂. Solve for T₂.  

(3.32 L)/(360 K) = (4.50 L)/(T₂)  

T₂ = 488 K.

4.  Do the same as above, but for V₂.  

(5.10 L)/(-56°C) = V₂/(-82°C)  

V₂ = 7.47 L

5.  Use the equation V₁/n₁ = V₂/n₂.  Solve for V₂.  

(37.2 L)/(0.750 mol) = (V₂)/(0.778 mol)  

V₂ = 38.6 L

6.  Do the same as above, but for n₂.

(86.0 L)/(2.65 mol) = (92.5 L)(n₂)  

n₂ = 2.85 mol

7.  Use the equation P₁/T₁ = P₂/T₂.  Solve for T₂.  

(3.00 atm)/(390 K) = (2.45 atm)/(T₂)  

T₂ = 319 K

8.  Do the same as above, but for P₂.  

In this specific case, however you will need to convert units.  Since both temperatures don't have the same sign, the ratio won't come out right.  Convert to Kelvin.  Add 273.15 to the temperature in Celsius to convert to Kelvin -12.3°C = 260.85 K  25°C = 298.15 K.

(3.00 kPa)/(260.85 K) = P₂/(298.15 K)

P₂ = 3.43 kPa

There is a lot in here... If you are confused about something, let me know!

6 0
3 years ago
4 physical properties of spoonfull of sugar
almond37 [142]
Small crystals 
<span>white, brown </span>
<span>hard as in solid at room temp </span>
<span>sweet </span>
3 0
3 years ago
Read 2 more answers
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