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neonofarm [45]
4 years ago
10

Silver is a white metal that is an excellent conductor of heat and electricity. The density of silver is 10.49 g/cm3. Silver doe

s not react with water but does react with nitric acid. Silver tarnishes when exposed to air. A physical property of silver is Silver reacts with nitric acid.
A.Silver reacts with nitric acid

B.Silver does not react with water

C.The density of silver is 10.49 g/cm3.

D.Silver tarnishes when exposed to air.
Chemistry
1 answer:
Aleks [24]4 years ago
8 0
C. The density of silver is 10.49 g/cm3
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What is the concentration of nitrate ion in a 425 mL solution containing 32.0 g of Mg(NO3)2 (M = 148.3)?
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Answer : The final concentration of copper(II) ion is, 0.198 M

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First we have to calculate the moles of CuSO_4 and CuI_2.

\text{Moles of }CuSO_4=\text{Concentration of }CuSO_4\times \text{Volume of solution}

\text{Moles of }CuSO_4=0.113mol/L\times 0.0406L=0.00459mol

Moles of CuSO_4 = Moles of Cu^{2+} = 0.00459 mol

and,

\text{Moles of }CuI_2=\text{Concentration of }CuI_2\times \text{Volume of solution}

\text{Moles of }CuI_2=0.329mol/L\times 0.0264L=0.00869mol

Moles of CuI_2 = Moles of Cu^{2+} = 0.00869 mol

Now we have to calculate the total moles of copper(II) ion and total volume of solution.

Total moles copper(II) ion = 0.00459 mol + 0.00869 mol

Total moles copper(II) ion = 0.0133 mol

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Total volume of solution = 40.6 mL + 26.4 mL = 64.0 mL = 0.067 L    (1 L = 1000 mL)

Now we have to calculate the final concentration of copper(II) ion.

\text{Final concentration of copper(II) ion}=\frac{\text{Total moles}}{\text{Total volume}}

\text{Final concentration of copper(II) ion}=\frac{0.0133mol}{0.067L}=0.198mol/L=0.198M

Thus, the final concentration of copper(II) ion is, 0.198 M

5 0
3 years ago
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