It is B balance, because it has a 0,01 g divisions scale. The minimun division in A balance is only 0,1 g, i.e, decigram measurement.
<span>There are a number of ways
to express concentration of a solution. This includes molarity. Molarity is
expressed as the number of moles of solute per volume of the solution.
Calculations are as follows:
Molarity of NO3 ion = 32.0 g Mg(NO3)2 ( 1 mol / 148.3 g ) ( 2 mol NO3 / 1 mol Mg(NO3)2) / .425 L
MOlarity of NO3 ion = 1.02 M </span><span>
</span>
Answer: As for vapor pressure being higher at higher temperatures, when the temperature of a liquid is raised, the added energy in the liquid gives the molecules more energy and they have greater ability to escape the liquid phase and go into the gaseous phase.
Explanation:
Answer : The final concentration of copper(II) ion is, 0.198 M
Explanation :
First we have to calculate the moles of
and
.


Moles of
= Moles of
= 0.00459 mol
and,


Moles of
= Moles of
= 0.00869 mol
Now we have to calculate the total moles of copper(II) ion and total volume of solution.
Total moles copper(II) ion = 0.00459 mol + 0.00869 mol
Total moles copper(II) ion = 0.0133 mol
and,
Total volume of solution = 40.6 mL + 26.4 mL = 64.0 mL = 0.067 L (1 L = 1000 mL)
Now we have to calculate the final concentration of copper(II) ion.


Thus, the final concentration of copper(II) ion is, 0.198 M