what are the x-intercepts of the graph of the function f(x) = x2 4x – 12? (–6, 0), (2,0) (–2, –16), (0, –12) (–6, 0), (–2, –16),
joja [24]
F(x) = x^2 + 4x - 12
x-intercepts are the values of x when y = 0
x^2 + 4x - 12 = 0
(x - 2)(x + 6) = 0
x - 2 = 0 or x + 6 = 0
x = 2 or x = -6
Therefore the x-intercepts are (-6, 0), (2, 0)
Answer:
Step-by-step explanation:
So we have the equation:
First, let's distribute the negative:
Combine like terms:
Subtract or add:
Subtract 6 from both sides:
Divide both sides by 3:
And we're done!
-12y+14-9y=14
-21y=0
y=0, x=7
F(-7) = -7 - 10
f(-7) = -17
Hope I helped!
Let me know if you need anything else!
<span>~ Zoe (Rank:'Genius')</span>
The correct answer is 4
100=25/X
X=4
