$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-11})~\hspace{10em} \stackrel{slope}{m}\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-11)}=\stackrel{m}{0}(x-\stackrel{x_1}{6}) \\\\\\ y+11=0\implies y=-11$

5 0

3 years ago

Anyone know this geometry question? Will give brainiest

Dafna11 [192]

The opposite angles equal each other, so X and Z are equal
using that we solve for x by setting them equal:

6x-60 = 2x+68

subtract 2x from each side:

4x -60 = 68

add 60 to each side:

4x = 128
divide both sides by 4
x = 128/4
x = 32

now we know x so we can solve everything else by replacing x with 32

WY = 3x+5 = 3(32)+5 = 96+5 = 101

angle Z = 2x+68 = 2(32)+68 = 64+132

the answer is C

5 0

3 years ago

Combine the like terms to create an equiva 4y - 4+ (-3) Stuck? Watch a video or use a hint.

jeka57 [31]

Answer:

Step-by-step explanation:

because

8 0

3 years ago