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lara31 [8.8K]
3 years ago
12

Calculate the magnetic field at 2m from a straight wire carrying a current of 5 A. (K = 2 x 10 ^-7)

Physics
1 answer:
blagie [28]3 years ago
6 0

Answer:

B=5\times 10^{-7}\ T

Explanation:

Given that,

Current in a wire, I = 5 A

We need to find the magnetic field at 2m from a straight wire carrying a current of 5 A.

The magnetic field due to a wire is given by :

B=\dfrac{\mu_0I}{2\pi r}\\\\B=\dfrac{4\pi \times 10^{-7}\times 5}{2\pi \times 2}\\\\B=5\times 10^{-7}\ T

So, the required magnetic field is 5\times 10^{-7}\ T.

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An object at rest is suddenly broken apart into fragments a and b by an explosion. the fragment a acquires three times the kinet
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4 years ago
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Read 2 more answers
Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weigh
PIT_PIT [208]

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value is F_j  =  550\ N

Explanation:

From the question we are told that

   The length of the stretcher is  d =  2.0 \  m

    The weight of the stretcher is W  =  100 \  N

    The weight for Wayne is  W_w =  800 \ N

     The distance of  center of gravity for Wayne from Chris is c_w = 75 cm  =  0.75 \ m

Generally taking moment about the first end where Chris is

         F_j *  d              => upward moment

Here F_j is the force applied by Jamie

Generally  taking moment about the second end where Jamie is

      W *  ( \frac{d}{2} ) +  W_w * (d - c_w)      => downward moment

Generally at equilibrium , the upward moment is equal to the downward moment

     F_j *  d = W *  ( \frac{d}{2} ) +  W_w * (d - c_w)

=>   F_j *  2  = 100 *  ( \frac{ 2}{2} ) +  800 * (2 - 0.75)

=>    F_j  =  550\ N

3 0
3 years ago
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