In 6 secs, the dog covers-
S=vt
8.9*6 = 53.4 m.
In the same time, the cat covers, 53.4-3.8 = 49.6 m.
Thus, speed of the cat, v= s/t,
= 49.6/6 = 8.267 m/s
-- The area under a velocity/time graph, between two points in time, is the difference in displacement during that period of time.
-- The area under a speed/time graph, between two points in time, is the distance covered during that period of time.
Answer:f^n=m(a+g)
Explanation:khan academy said
Density =mass/volume 120/200 =0.6 g/cm
What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds? Help hello
