All categories

4 years ago

Does exists the friction force in space?If yes,tell an full example

1 answer:

5 0

Yes, friction does exist in space. Friction has nothing to do with the earth's atmosphere. It exists everywhere in the universe. <span />

You might be interested in

A lightbulb has a resistance of 195 Ω and carries a current of 0.62 A.

ki77a [65]

Answer:

Explanation:

Power is current times voltage:

P = IV

Voltage is current times resistance:

V = IR

Therefore:

P = I²R

Given I = 0.62 A and R = 195 Ω:

P = (0.62 A)² (195 Ω)

P ≈ 75 W

8 0

3 years ago

If a 0.200-kilogram ball sits on a shelf 2.00 meters from the floor, how much mechanical energy (me) does it possess? More than

iogann1982 [59]

Answer:

Mechanical energy = 3.92 J

exactly 3.92 j

Explanation:

As we know that mechanical energy is sum of kinetic energy and potential energy of the system

so here we can say that mechanical energy is sum of kinetic energy of ball and its potential energy

Since ball is at rest so kinetic energy of the ball must be ZERO

Now for potential energy we know that

$U = mgh$

now we know

m = 0.2 kg

h = 2 m

now for potential ene'rgy

$U = (0.20)(9.8)(2)$

$U = 3.92 J$

so mechanical energy is given as

Mechanical Energy = 3.92 + 0 = 3.92 J

5 0

3 years ago

1. Two magnets are placed on a table, and they immediately move to attach to each other. Which statement is correct about the en

erma4kov [3.2K]

Answer: 1: kinetic energy and velocity are at zero when the magnets are held apart, and both increases rapidly when they are released and move together. Energy stored in the magnetic field decreases.

2: The energy stored in the system is converted to kinetic, thermal, and sound energy.

3: The energy stored in the magnetic field does not change.

4: Some of the energy stored is converted into kinetic and thermal energy.

5: Two small repelling magnets hold each other in place.

Just took the quiz all are correct! I hope this helps you! :)

3 0

3 years ago

If the car passes point A with a speed of 20 m/s and begins to increase its speed at a constant rate of at = 0.5 m/s2 , determin

IceJOKER [234]

Answer:

$1.68 \frac{m}{s^2}$

Explanation:

Please find the image for the question as attached file.

Solution -

Given -

First of all we will calculate the velocity at point C,

As per newton's third law of motion-

$V_C^2 = V_A^2 + 2 a_t (S_C - S_A)\\$

Substituting the given values in above equation, we get -

$V_C^2 = 20^2 + 2*0.5*(100-0)\\V_C = 22.361 \frac{m}{s}$

Now we will determine the radius of curvature for the curve shown in the attached image

$Y = 16 - \frac{1}{625} X^2\\$

Differentiating on both the sides, we get -

$\frac{dy}{dx} = -3.2 (10^-3) X\\\frac{d^2y}{d^2x} = -3.2 (10^-3)\\Curve = \frac{[1+(\frac{dy}{dx})^2]^{\frac{3}{2}} }{\frac{d^2y}{d^2x}} \\Curve = 312.5$ meter