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kkurt [141]
3 years ago
15

123g is rounded to nearest Whole. Write down the maximum possible mass it could have been.

Mathematics
1 answer:
siniylev [52]3 years ago
6 0

It is rounded to 100 grams

122.5g ≤ mass < 123.5g For calculation purposes a maximum value of 123.5 grams can be used.

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A line passes through the point (-6,4) and has a slope of 5/2
matrenka [14]
The equation in slope intercept for is y = 5/2x + 4

The y intercept is 4
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An 8 foot square floor is to be covered with square tiles measuring 8 inches on each side. If each tile costs 50 cents, how much
wariber [46]

9514 1404 393

Answer:

  (c) $72

Step-by-step explanation:

Each tile is 8/12 ft = 2/3 ft on a side. Then 8/(2/3) = 12 tiles will fit along each edge of the square area to be tiled. That is ...

  12 × 12 = 144

tiles will be needed to cover the area.

The cost of 144 tiles at $0.50 each is ...

  (144)($0.50) = $72.00

8 0
3 years ago
The base of a 6-inch long ice cream cone with a diameter of 2 inches, is cut 0.25 inches from the base. This cut creates two sha
Tamiku [17]

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Length of ice cream cone = 6 inch

Diameter of cone = 2 inches

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\frac{2}{2}=1\ in.

But according to question, it is cut 0.25 inches from the base  and this cut into cylinder and cone.

Since it was cut so close to the base.

So, Height of the cylinder = 0.25 inches

As we know the  formula for "Volume of cylinder ":

Volume=\pi r^2h\\\\Volume=\frac{22}{7}\times 1\times 1\times 0.25\\\\Volume=0.785\ in^3\\\\Volume=0.79\ in^3

Hence, Option 'C' is correct.

7 0
3 years ago
Rewrite the equation in slope-intercept form. x=4y+2
Dafna1 [17]

Answer:

y = x/4 - 1/2

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Step 1: Write equation

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7 0
3 years ago
Read 2 more answers
Identify the correct corresponding parts
andrey2020 [161]

Answer:

The correct corresponding part is;

\overline {CB} ≅ \overline {CD}

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment \overline {CA} is congruent to \overline {CE} ( \overline {CA} ≅ \overline {CE})

Segment \overline {CB} is congruent to \overline {CD} ( \overline {CB} ≅ \overline {CD})

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment \overline {AB} is congruent to \overline {DE} (\overline {AB} ≅ \overline {DE}) by CPCTC

Segment \overline {AE} bisects \overline {BD}

Segment \overline {BD} bisects \overline {AE}

Therefore, the correct option is \overline {CB} ≅ \overline {CD}

3 0
2 years ago
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