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3 years ago

PLZ HELP DUE IN 10 MINUTES

Physics

1 answer:

likoan [24]3 years ago

6 0

Answer:50%

Explanation: put it you are in a hurry

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Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with the

scoundrel [369]

Answer:

F = 0.1575 N

Explanation:

When the third sphere touches the first sphere, the charge is distributed between both spheres, then now the first sphere has only half of his original charge.

In this moment then

Sphere one has a charge = Q/2

Sphere three has a charge = Q/2

Now when the third sphere touches the second sphere again the charge is distributed in a manner that both sphere has the same charge.

How the total charge is Q = Q/2 + Q = 3/2Q, when the spheres are separated each one has 3/4Q

Sphere two has a charge = 3/4Q

Sphere three has a charge = 3/4Q

The electrostatic force that acts on sphere 2 due to sphere 1 is:

F = $\frac{kQ_{1}Q_{2} }{r^{2} }$

F= $\frac{K(Q/2)(3Q/4)}{r^{2} }$

how $\frac{KQ^{2} }{r^{2} }$ = 0.42

Then

F = $\frac{0.42*3}{8}$

F = 0.1575 N

3 0

3 years ago

A snowboarder starts from rest on an inclined planar snow surface and gives herself a tiny push to start sliding down the hill.

tiny-mole [99]

Answer:

v = 26.52 m/s

Explanation:

Here we know that as she passes the flag she will gain some speed

so here we can say that

Work done by all forces = change in kinetic energy of the system

so we will have

$W_g + W_f = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

here we know that

$W_g = mgh$

$W_f = -\mu mg d$

$v_i = 0$

h = 39.78 m

d = 27.81 m

so we have

$mgh - \mu mg d = \frac{1}{2}mv^2 - 0$

$(9.8)(39.78 - (0.14)(27.81)) = \frac{1}{2} v^2$

$v = 26.52 m/s$

8 0

3 years ago

Someone who is good at physics please help me out! i’ll give out brainliest answers

alexgriva [62]

Answer:

450m

Explanation:

You would use the equation x-x0=0.5(v0+v)t as you have the time and velocities. x-x0(Change in position/displacement)=0.5(0+30)30. The distance will be 450m.

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3 years ago

When steam condenses

9966 [12]

A is the correct answer

3 0

3 years ago

Read 2 more answers

How many aluminium ions are needed to cross an ammeter if you want a current of 3A?

Reptile [31]

Assuming that the time needed to cross the ammeter is 1 hour or 3600s, then using coloumb's law,
I x t = F x m / (eq. wt)

Using the given values and formula:
3 x 3600 = 96500 x m / (27/3)

Solving for m,
m = 1.007 g of Al3+

6 0

4 years ago