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2 years ago

In the lab, You have a highly reactive metal like sodium. It is so reactive that water sets it off. How would you store it?

Physics

1 answer:

kenny6666 [7]2 years ago

8 0

Answer:

Sodium is stored under paraffin oil

Explanation:

Group 1 metals are known to be very highly reactive. The chemical reactivity of the members of the group decreases down the group.

Sodium reacts violently with water and upon exposure to the atmosphere. As a result of this, it must be stored under paraffin oil.

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A Meteorite Strikes On October 9, 1992, a 27-pound meteorite struck a car in Peekskill, NY, leaving a dent 22 cm deep in the tru

vagabundo [1.1K]

Answer:

Acceleration of the meteorite, $a=-38409.09\ m/s^2$

Explanation:

It is given that,

A Meteorite after striking struck a car, v = 0

Initial speed of the Meteorite, u = 130 m/s

Distance covered by Meteorite, s = 22 cm = 0.22 m

We need to find the magnitude of its deceleration. It can be calculated using the third equation of motion as :

$a=\dfrac{v^2-u^2}{2s}$

$a=\dfrac{-(130)^2}{2\times 0.22}$

$a=-38409.09\ m/s^2$

So, the deceleration of the Meteorite is $-38409.09\ m/s^2$ . Hence, this is the required solution.

7 0

2 years ago

Use Eq. cosϕ=R/Z to show that the average power delivered by the source in an L−R−C series circuit is given by Pav = I^2rmsR .

Evgen [1.6K]

Answer:

Explanation:

In a L C R circuit, the average power is given by

$P_{av}=V_{rms}I_{rms}Cos\phi$

As given in the question

CosФ = R / Z

And we know that

$V_{rms}=I_{rms}\times Z$

$P_{av}=I_{rms}\times Z\times I_{rms}\times \frac{R}{Z}$

$P_{av}=I_{rms}^{2}\times R$

6 0

2 years ago

At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m². A fan is 30 m from the loudspeak

Klio2033 [76]

To solve this problem we will apply the concepts related to the Area, the power and the proportionality relationships between intensity and distance.

The expression for sound power is,

$P = AI$

Here,

A = Area

I = Intensity

P = Power

At the same time the area can be written as,

$A = \frac{\pi d^2}{4}$

Now the intensity is inversely proportional to the square of the distance from the source, then

$I \propto \frac{1}{r^2}$

The expression for the intensity at different distance is

$\frac{I_1}{I_2}= \frac{r^2_2}{r_1^2}$

Here,

$I_1$ = Intensity at distance 1

$I_2$ = Intensity at distance 2

$r_1$ = Distance 1 from light source

$r_2$ = Distance 2 from the light source

If we rearrange the expression to find the intensity at second position we have,

$I_2 = I_1 (\frac{r_1^2}{r_2^2})$

If we replace with our values at this equation we have,

$I_2 = (0.10W/m^2)(\frac{1.0m^2}{30.0m^2})$

$I_2 = 1.11*10^{-4} W/m^2$

Now using the equation to find the area we have that

$A = \frac{\pi (8.4*10^{-3}m)^2}{4}$

$A = 5.5*10^{-5}m^2$

Finally with the intensity and the area we can find the sound power, which is

$P = AI$

$P = (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)$

$P = 6.1*10^{-9}J/s$

Power is defined as the quantity of Energy per second, then

$E = 6.1*10^{-9}J$

8 0

3 years ago

Light travels 300,000,000 m/s, and one year has approximately 32,000,000 seconds. a light year is the distance light travels in

irina [24]

300 000 000 m/s in km/s

1000 m = 1km

300 000 000 m/s = 3 * 10⁸ m/s = 3 * 10⁵ *10³ m/s

= 3 * 10⁵ *10³ m/s

= 3 * 10⁵ km/s

Speed = 3 * 10⁵ km/s

6 0

3 years ago

Read 2 more answers

What is the difference between an open and closed circuit?

exis [7]

A closed circle means the number is included and an open circle means its not.

7 0

2 years ago