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Talja [164]
3 years ago
15

Help me do this math problem C= 59(F−32)

Mathematics
1 answer:
dybincka [34]3 years ago
7 0

Answer:

c=59f-1888

f=\frac{c}{59}+32

Step-by-step explanation:

Hope this helps!

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3 0
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WILL MARK BRAINLIEST
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Answer:

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Step-by-step explanation:

8 0
4 years ago
For the rational expression 2x^2-7x-15/x^2-25, do both of the following,
Mrrafil [7]

Answer:

a. \frac{2x + 3}{x+5}

b. x ≠ -5 (Vertical asymptote) and x ≠ 5 (Hole)

Step-by-step explanation:

Factor the numerator (Grouping):

2x^2 - 7x - 15              

Two numbers that multiply to -30 and add to -7 = -3 and 10

[2x^2 - 10x] + [3x - 15]

(2x + 3)(x - 5)

Factor the denominator (Difference of Two Squares):

x^2 - 25 = (x +5)(x-5)

Factored Expression:

(x - 5) can be factored out of top and bottom as a hole-

\frac{(2x + 3)(x - 5)}{(x + 5)(x - 5)} = \frac{2x + 3}{x+5}

Variable Restrictions:

Denominator ≠ 0

x + 5 = 0\\x = -5

Vertical asymptote at x = -5 ⇒ x ≠ -5

3 0
3 years ago
Which of the following rational functions is graphed below?
Viefleur [7K]
A I think is the answer
7 0
3 years ago
A valve in a full 6000 gallon water tank is slowly opening. Water flows out of the tank through the valve. The flow rate in gall
Wittaler [7]
The volume of the gallon is 6000 gallon
the rate of water flow per min is f(t)=300t^2
a] amount of water that flowed in the first 7 minutes=7/60 hours will be:
f(7)=300(7/60)^2
solving the above we get
f(7)=7/12 gallons

b] The time taken for the tank to be empty will be as follows:
amount of water that will flow out for the tank to be empty will be 6000 gallons
thus,
6000=300t^2
this can be simplified to
20=t^2
t^2-20=0
solving this we get:
t=-2√5 or 2√5
the time taken for the tank to be empty will be t=2√5 hours=5.4721 hours



8 0
3 years ago
Read 2 more answers
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