2 years ago

How would you classify the number 121 ?

1 answer:

Maslowich2 years ago

5 0

Answer:

$\boxed{121\: is \: a \: perfect \: square}$

Step-by-step explanation:

$the \: \sqrt[3]{121} \: is \: not \: a \: perfect \: cube \\ but \\ the \: \sqrt{121} = 11 \to \: is \: a \: perfect \: square \\$

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aivan3 [116]

<h3><u>Answer</u> :</h3>

$\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}$

Let's solve !

$:\implies\sf\:25^{\frac{3}{2}}$

$:\implies\sf\:(\sqrt[2]{25})^3$

$:\implies\sf\:5^3$

$:\implies\boxed{\bf{\red{125}}}$

<u>Hence, Oprion-D is correct</u> !

7 0

3 years ago

jek_recluse [69]

3 x 8 = 24

3 x -2 = -6

reply if you this was wrong or you needed a different answer pls >:(

3 0

3 years ago

dalvyx [7]

Three hundred and nine thousand and seventeen

3 0

2 years ago

IceJOKER [234]

Answer:

I would say d.im pretty sure tho

6 0

2 years ago

Kryger [21]

Answer:

C times 23

Step-by-step explanation:

8 0

3 years ago

How would you classify the number 121 ?​