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White raven [17]
3 years ago
15

How would you classify the number 121 ?​

Mathematics
1 answer:
Maslowich3 years ago
5 0

Answer:

\boxed{121\:  is \:  a \: perfect \: square}

Step-by-step explanation:

the \:  \sqrt[3]{121}  \: is \: not \: a \: perfect \: cube \\ but \\ the \:  \sqrt{121}  = 11 \to \: is \: a \: perfect \: square \\

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Please help!!!!!!!!! ​
MArishka [77]

Answer:

Step-by-step explanation:

The point means that 15 pounds of beans cost 12 dollars.

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3 years ago
Someone please help! find x round to the nearest tenth! trigonometry!​
TEA [102]

Answer:

<h2>x = 745.5 ft</h2>

Step-by-step explanation:

Look at the picture.

Use sine:

sine=\dfrac{opposite}{hypotenuse}

We have a measure of the angle and length of the opposite:

\alpha=28^o,\ opposite=350\ ft

\sin28^o\approx0.4695

Substitute:

\dfrac{350}{x}=0.4695

\dfrac{350}{x}=\dfrac{4695}{10000}            <em>cross multiply</em>

4695x=3500000           <em>divide both sides by 4695</em>

x=\dfrac{3500000}{4695}\to x\approx745.5

5 0
3 years ago
In class, Matthew stated, "I think that a negative is like an opposite. That is why multiplying a negative times a negative equa
Black_prince [1.1K]
Two negatives being multiplied DOES equal a positive 
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3 0
3 years ago
Suppose a production facility purchases a particular component part in large lots from a supplier. The production manager wants
musickatia [10]

Answer:

We need a sample size of at least 1161.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error for the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.22

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large a sample should she take?

We need a sample size of at least n.

n is found when M = 0.02

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.645\sqrt{\frac{0.22*0.78}{n}}

0.02\sqrt{n} = 1.645\sqrt{0.22*0.78}

\sqrt{n} = \frac{1.645\sqrt{0.22*0.78}}{0.02}

(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.22*0.78}}{0.02})^{2}

n = 1160.88

Rounding up

We need a sample size of at least 1161.

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4 years ago
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Answer:

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Read 2 more answers
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