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4 years ago

Find the area of the regular polygon.

Mathematics

2 answers:

Shkiper50 [21]4 years ago

8 0

The height of the triangle is 5√3. The area is 1/2(base x height). The first choice is correct.

ollegr [7]4 years ago

4 0

Area of equilateral triangle = s²√3/4

A = 10 *10√3 / 4 = 25√3

A = 25√3

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Imani has 2 part-time jobs. One pays $7.50 per hour for dog grooming, and the other pays $8.25 per hour at a grocery store. Help

g100num [7]

Answer:

‘d’ represents dog grooming
‘g’ represents grocery store

7.50d+8.25g ≤ 500

All money has to be exactly equal to $500, or less than.

6 0

3 years ago

What is the slope of the line that passes through each pair of points A(-2, -4), B(2,4)

zhannawk [14.2K]

The slope is 2 hope this helps

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4 years ago

Optimization? The top and bottom margins of a poster are each 6 cm and the side margins are each 4 cm. If the area of printed ma

Alisiya [41]

The demension with the smallest are would be 48cm

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3 years ago

What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –(x – 6) and passes through

Sever21 [200]

That line is in point-slope form:

$\sf y-y_1=m(x-x_1)$

Where 'm' is the slope and (x1, y1) is a point on the line.

Perpendicular lines have opposite slopes. To get the opposite, we take the reciprocal and multiply it by -1.

$\sf -1$

Reciprocal:

$\sf -\dfrac{1}{1}\rightarrow -\dfrac{1}{1}\rightarrow -1$

Multiply by -1:

$\sf 1$

We can plug this slope and the point into point-slope form, and then convert it to slope-intercept form.

$\sf y-y_1=m(x-x_1)$

$\sf y-(-2)=1(x-(-2))$

Negatives cancel out:

$\sf y+2=1(x+2)$

Distribute 1 into the parenthesis:

$\sf y+2=x+2$

Subtract 2 to both sides:

$\boxed{\sf y=x}$

8 0

3 years ago

1. f(x) = 3x - 2<br> Domain: (-2, 0,4)

kifflom [539]

Step-by-step explanation:

Since the calculations are very easy, I'll just focus on what you actually have to ask yourself to solve the exercise.

Domain: the question you have to ask yourself is "which numbers my function will accept as an input?" or, equivalently, "which numbers my function will not accept as an input?"

From the second question, we know that there are some functions with domain issues: for example, if there is a denominator, you must be sure that it isn't zero, since you can't divide by zero. So, that function wouldn't accept as input the values which annihilate the denominator.

In general, you have domain issues with:

Denominator (cannot be zero);

Even roots (they can't be computed for negative numbers);

Logarithms (they can't be computed for negative numbers, or zero).

Is this case, you have none of the three above, and so you have no domain issues. Alternatively, you could just see that your function picks a number

, multiplies it by

, and then adds

, and of course you can multiply any number by

, and you can add

to any number.

Range: now you should ask: which values can I obtain from my functions? I say that you can obtain every possible value. Let's say that you want to obtain a particular number

. So, you need to find a number

such that

, and the equation easily solves for

, with

−

So, if you choose any number

, I can tell you that it is the image of a particular

, namely

−

, and again, this algorithm is ok for any

, you simply need to subtract

and then divide the whole thing by

, which again are operations you are always allowed to do.

3 0

3 years ago