Hello :
<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b
f(x) x²+4x+4+b= x² +4x-5
4+b= -5
b = -9
the vertex is : (2 , -9)
Answer:

Step-by-step explanation:

Answer:
5 Batches.
Step-by-step explanation:
5*1/6 = 5/6
The last one if I'm not mistaking
All real solutions
Everything cancels out once you multiply the top equation by two.
0 = 0 which means all real answers.
I hoping you meant question 3. Good luck!