A plastic rod becomes negatively charged when it is rubbed with a piece of wool. How does the rod become charged?
2 answers:
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When light crosses the interface between a medium with higher refractive index and a medium with lower refractive index, there is a maximum value of the angle of incidence after which there is no refraction, but all the light is reflected, and this maximum value is called critical angle.
The critical angle is given by
where n1 is the refractive index of the first medium while n2 is the refractive index of the second medium. In our problem, n1=1.33 and n2=1.58, so the critical angle is
The critical angle is given by
where n1 is the refractive index of the first medium while n2 is the refractive index of the second medium. In our problem, n1=1.33 and n2=1.58, so the critical angle is
Answer:
a)1.93 kg-m^2
b) 1.45 kg-m^2
c) = 0
d) 1.15 kg-m^2
Explanation:
mass of the bar M = 4 kg
length of the bar = 2 m
mass of balls m1= m2= 0.3 kg
moment of inertia of bar
about an axis perpendicular to the bar through its center.
a) MOI of bar + 2×m×(L/2)^2
+
now putting the values of m, M and L as above and solving we get
I= 1.93 kg-m^2
b) perpendicular to the bar through one of the balls
= 1.45 kg-m^2
c) parallel to the bar through both balls
zero as the no mass distribution along the parallel to the bar through both balls.
d) parallel to the bar and 0.500 m from it.
I=
putting values and solving we get
1.15 kg-m^2