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maxonik [38]
3 years ago
10

How do I solve this question the answer I should get is C

Physics
2 answers:
prisoha [69]3 years ago
7 0
Your right. It's C. This question is difficult
xenn [34]3 years ago
4 0
So sorry for my mistake,
Change in density= 1.22-0.74=0.48
Pressure (1-0.48)(100000)=520000
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How early do you think i should start saving and searching for scholarships and state aid
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How are human cheek cells and human skin cells similar and different​
KonstantinChe [14]

Answer:

human cheek cell has got a nucleus, rbc doesnot

human cheek cell is found in the cheeks n made there whereas rbc is made in the bonemarrow and found in blood

human cheek cell serves the function of supplying nutrition to cheek by simply exchange while rbc transports oxygen around the body..

cheek cell can reproduce rbc cannot asit is non nucleated.The epithelial cells in the lining of the mouth are referred to as basal mucosa and divide roughly every 24 hours. They can easily be obtained through a simple swab or a mouth rinse. The cheek cell is very simple, but it contains the entire genetic makeup of the person's body. For this reason, cheek cells are frequently used to establish paternity and other investigations involving DNA. More recently, researchers have discovered that the cheek cell can be used to measure a person's likelihood of having high blood pressure.

A human cheek cell is thin, flat and irregularly shaped and has a large nucleus that contains the DNA. Its plasma membrane helps the cell to maintain suitable temperature while giving it its shape. Since it is selectively permeable, it only allows certain molecules into and out of the cell. Its cytoplasm contains water that dissolves nutrients and enzymes. It is an animal cell so it is different from plant cell.and the difference will be same as that with animal cell

6 0
3 years ago
Read 2 more answers
What evidence did astronomers use to prove jets travel in opposite directions?
mr Goodwill [35]

The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.

<h3>Who are the astronomers?</h3>

Astronomer is a person who study astronomy which is a scientific study that has to do with space, space bodies, comets, planets, stars and so on.

Therefore, The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.

Learn more about astronomers below.

brainly.com/question/10826203

#SPJ11

7 0
2 years ago
Read 2 more answers
a ball kicked with a velocity of 8m/s at an angle of 30 degree to horizontal. calculate the time of flight of the ball. (g=10ms^
posledela

Answer:

Approximately 0.8\; \rm s (assuming that air resistance is negligible.)

Explanation:

Let v_0 denote the initial velocity of this ball. Let \theta denote the angle of elevation of that velocity.

The initial velocity of this ball could be decomposed into two parts:

  • Initial vertical velocity: v_0(\text{vertical}) = v_0 \cdot \sin(\theta).
  • Initial horizontal velocity: v_0(\text{vertical}) = v_0 \cdot \cos(\theta).

If air resistance on this ball is negligible, v_0(\text{vertical}) alone would be sufficient for finding the time of flight of this ball.

Calculate v_0(\text{vertical}) given that v_0 = 8 \; \rm m \cdot s^{-1} and \theta = 30^\circ:

\begin{aligned}& v_0(\text{vertical}) \\ &= v_0 \cdot \sin(\theta) \\ &= \left(8 \; \rm m \cdot s^{-1} \right) \cdot \sin\left(30^{\circ}\right) \\ &= 4\;\rm m \cdot s^{-1} \end{aligned}.

Assume that air resistance on this ball is zero. Right before the ball hits the ground, the vertical velocity of this ball would be exactly the opposite of the value when the ball was launched.

Since v_0(\text{vertical}) = 4\; \rm m \cdot s^{-1}, the vertical velocity of this ball right before landing would be v_1(\text{vertical}) = -4\; \rm m \cdot s^{-1}.

Calculate the change to the vertical velocity of this ball:

\begin{aligned}& \Delta v(\text{vertical}) \\ & = v_1(\text{vertical}) - v_0(\text{vertical}) \\ &= -8\; \rm m \cdot s^{-1}\end{aligned}.

In other words, the vertical velocity of this ball should have change by 8\; \rm m \cdot s^{-1} during the entire flight (from the launch to the landing.)

The question states that the gravitational field strength on this ball is g = 10\; \rm m \cdot s^{-2}. In other words, the (vertical) downward gravitational pull on this ball could change the vertical velocity of the ball by 10\; \rm m\cdot s^{-1} each second. What fraction of a second would it take to change the vertical velocity of this ball by 8\; \rm m \cdot s^{-1}?

\begin{aligned}t &= \frac{\Delta v(\text{initial})}{g} \\ &= \frac{8\; \rm m \cdot s^{-1}}{10\; \rm m \cdot s^{-2}} = 0.8\; \rm s\end{aligned}.

In other words, it would take 0.8\; \rm s to change the velocity of this ball from the initial velocity at launch to the final velocity at landing. Therefore, the time of the flight of this ball would be 0.8\; \rm s\!.

5 0
3 years ago
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