Answer:
The probability of the chosen ball being shiny conditional on it being red is; 0.375
Step-by-step explanation:
Let A be the event that a red ball has been chosen
Let B be the event that a shiny ball has been chosen
Let S be the total outcomes = 150 balls
Thus;
P(A ∩ B ) = 36/150
A ∩ B' = 150 - 36 - 54
A ∩ B' = 60
Thus; P(A ∩ B') = 60/150
P(A') = 54/150
P(A) = (150 - 54)/150 = 96/150
Thus, probability of the chosen ball being shiny conditional on it being red is;
P(B | A) = P(B ∩ A)/P(A)
Thus; P(B | A) = (36/150)/(96/150)
P(B | A) = 0.375
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The answer would be D i think because if the two angles are to equal 72, and one of the angles equals 42, 72-42= 30. to find x, you’d do 30/6 which equals 5. so x=5 and the angle measure would be 30
Answer:
a. $45.86
b. $43.87
c. Percentage change = -4.40%)
Step-by-step explanation:
a. Let the price of share at the beginning of first year be represented with X
Now, Price of company's share dropped by 3.50% at the end of first year.
So, Price of share at the end of first year = x - 3.5% of x
= x - 0.035x
= 1x - 0.035x
= 0.965x
But it is equal to $44.25
=> 0.965x = 44.25
x = 44.25 / 0.965
x = 45.8549223
x = $45.86
b. During second year price of share decreased by $1.99. Therefore, Price of share at the end of second year = $45.86 - $1.99 = $43.87
c. Percentage change in the price of shares over two years = {(45.86 - 43.87)/45.86} *100
= (1.99/45.86)*100
= 0.04339294 * 100
= 4.40%
Now, as price of shares has dropped, the percentage change will be negative. (Δ% = -4.40%)
Hello :
all points <span>lies on a circle with a radius of 5 units and center at P(6, 1)are :
M(x,y) : (x-6)² + (y-1)² = 25</span>
