M<UWV =180- 99 -36= 45
45 = 1/2(94+20- arcUV)
45=57 - arcUV/2
arcUV / 2 = 57-45
arcUV / 2 =12
arcUV = 12(2)
arcUV = 24
answer is B. 24
probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
Answer:
Explanation:
so its referring to perimeter.
you add all values together.
this would equal 34.995 .
so, its 34.995 meters of fencing.
