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ale4655 [162]
3 years ago
6

Math question need help solving

Mathematics
1 answer:
pochemuha3 years ago
5 0

Answer:

where are my glasses

Step-by-step explanation:

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Help please fast .. this is in the class
NemiM [27]

Answer:

3 is correct answer

Step-by-step explanation:

root 2 and pi are irrational numbers

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B7%7D%7B2%7D%5E%7B2%7D-%5Cfrac%7B3%7D%7B4%7D%5E%7B1%7D%29%2A%5Cfrac%7B1%7D%7B3%7D"
KIM [24]
The answer is = 7 11/12
7 0
3 years ago
Read 2 more answers
A red light flashes every 14 minutes. A blue light flashes every 24 minutes. When will the two lights flash together again, if t
kkurt [141]

The least common multiple of 14 and 24 is 168.

The lights flash together every 168 minutes.

168 minutes = 2 hours 48 minutes.

If they flashed together at 8 AM, then they'll flash
together again at 10:48 AM.

3 0
3 years ago
the sum of two numbers is zero. when 15 times the smaller numbers is added to 10 times the larger, the result is 1. find the two
EleoNora [17]

We have two numbers say a, b. And a system of equations.

a+b=0\wedge\dfrac{a+b}{15}+10(a+b)=1

It looks a bit intimidating but it's actually very easy.

Instead of term a + b in the second equation we can say it's zero because the first equation describes a + b as being equal to 0.

So,

\dfrac{0}{15}+10\cdot0=1\Longrightarrow 0+0=1

The above equation is not true therefore numbers a and b do not exists in the real number domain.

a,b\notin\mathbb{R}

No solution.

Hope this helps.

7 0
3 years ago
A restaurant is offering selected three-course meals for one price. Customers can choose from 2 appetizers, 3 main courses, and
il63 [147K]
Ways of choosing 3 course meal 5*10*4=200 Ways of choosing 2 course meal (5*10)+(5*4)+(10*4)=110 Ways of choosing 1 course meal 5+10+4=19

possible ways of choosing at least 1 option: =(ways of choosing 3 course meal)+(ways of choosing 2 course meal)+(ways of choosing 1 course meal)= 200+110+19=329

329 combinations.
7 0
4 years ago
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