Answer:
1) Favor formation of reactant
2) Favor formation of product
3) Favor formation of product
4) Favor formation of product
5) Favor formation of product
Explanation:
The reaction is 
The reaction is endothermic
1. Adding hydrobromic acid (HBr)
It will increase the amount of bromide ion. Bromide ion is one of the product so it will favor formation of reactant.
2. Lowering the concentration of bromide (Br-) ions
As we are decreasing the the concentration of product it will favor formation of more products
3. Heating the concentrations
If we are heating the mixture, it will increase the temperature and it will favor endothermic reaction. Thus will favor formation of product.
4. Adding solid silver bromide (AgBr)
If we are adding silver bromide it means we are increasing the concentration of reactant, it will favor formation of products
5. Removing silver (Ag+) ions
Removing silver ions means we are decreasing the concentration of product thus it will favor formation of products.
Polar will always have the higher boiling point because they have strong van der waal forces
Answer:
Question: What Is The Correct IUPAC Name For S2F8? X ( ( (I) (IV) Di- Mono- Penta- Tetra- Tri- Hepta- Octa- Hexa- Fluorine Selenide Flourate Sulfide Sodium Sulfate Sulfur Fluoride Hydrate Acid.
Explanation:
Molar mass of HBr = 81 g/mol
Molar mass of nitrogen dioxide gas = 46 g/mol
Molar mass of ethane = 30 g/mol
Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:
So, the gas with least molar mass will effuse out fastest from the container and that is ethane gas.
The formula for average kinetic energy is:
where,
k = Boltzmann’s constant = 
T = temperature = 273.15 K ( at STP)
As we can see from the formula that kinetic energy depends upon only temperature of the gas molecule.
So, from this we can say that all the gas molecules have the same average kinetic energy at this temperature.
Answer:
The enthalpy of the solution is -35.9 kJ/mol
Explanation:
<u>Step 1:</u> Data given
Mass of lithiumchloride = 3.00 grams
Volume of water = 100 mL
Change in temperature = 6.09 °C
<u>Step 2:</u> Calculate mass of water
Mass of water = 1g/mL * 100 mL = 100 grams
<u>Step 3:</u> Calculate heat
q = m*c*ΔT
with m = the mass of water = 100 grams
with c = the heat capacity = 4.184 J/g°C
with ΔT = the chgange in temperature = 6.09 °C
q = 100 grams * 4.184 J/g°C * 6.09 °C
q =2548.1 J
<u>Step 4:</u> Calculate moles lithiumchloride
Moles LiCl = mass LiCl / Molar mass LiCl
Moles LiCl = 3 grams / 42.394 g/mol
Moles LiCl = 0.071 moles
<u>Step 5:</u> Calculate enthalpy of solution
ΔH = 2548.1 J /0.071 moles
ΔH = 35888.7 J/mol = 35.9 kJ/mol (negative because it's exothermic)
The enthalpy of the solution is -35.9 kJ/mol
