HELP QUICK I HAVE A QUIZ ITS JUST MULTIPLE CHOICE

(a) Write the dissolution reaction for solid Na2CO3 below. (Use the lowest possible coefficients. Include states-of-matter under

Andreas93 [3]

Answer:

For a: The chemical equation for the dissolution of sodium carbonate is $Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)$

For b: The net acid-base reaction is $CO_3^{2-}(aq.)+H_2O(l)\rightarrow OH^-(aq.)+HCO_3^-(aq.)$

Explanation:

For a:

Dissolution reaction is defined as the reaction in which a solid compound gets dissolved in water to form aqueous solution.

The chemical equation for the dissolution of sodium carbonate follows:

$Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)$

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.

The chemical equation for the ionization of sodium carbonate follows:

$Na_2CO_3(aq.)\rightarrow 2Na^+(aq.)+CO_3^{3-}(aq.)$

For b:

Now, the anion formed which is $CO_3^{2-}$ reacts with water to form conjugate acid.

The chemical equation for the reaction of anion with water follows:

$CO_3^{2-}(aq.)+H_2O(l)\rightarrow OH^-(aq.)+HCO_3^-(aq.)$

Hence, the net acid-base reaction of the anion formed and water is written above.

3 0

3 years ago

In a single displacement reaction between Sodium Phosphate and Barium, how much of each product (in grams) will be formed from 1

mixer [17]

Answer:

14.6 g of barium phosphate

3.35 g of sodium metal

Explanation:

2Na3PO4(aq) + 3Ba(s) -------> Ba3(PO4)2(aq) + 6Na(s)

The first step in any such reaction is to but down the balanced reaction equation according to the stoichiometry of the reaction.

The two products formed are barium phosphate and sodium metal.

Number of moles of barium corresponding to 10.0g of barium = mass of barium/ molar mass of barium

Molar mass of barium = 137.327 g

Number of moles of barium = 10/137.327

Number of moles of barium = 0.0728 moles

For barium phosphate;

3 moles of barium yields 1 mole of barium phosphate

0.0728 moles yields 0.0728 moles × 1/3 = 0.0243 moles of barium phosphate

Molar mass of barium phosphate = 601.93 g/mol

Therefore mass of barium phosphate = 0.0243 moles × 601.93 g/mol = 14.6 g of barium phosphate

For sodium metal

3 moles of barium yields 6 moles of sodium metal

0.0728 moles of barium yields 0.0728 × 6 / 3 = 0.1456 moles of sodium

Molar mass of sodium metal= 23 gmol-1

Mass of sodium metal= 0.1456g × 23 gmol-1 = 3.35 g of sodium metal

4 0

3 years ago

In a 66.0-g aqueous solution of methanol, CH 4 O , CH4O, the mole fraction of methanol is 0.300. 0.300. What is the mass of each

Mumz [18]

Answer:

The solution is composed by 37.5 g of water and 28.5 g of methanol.

Explanation:

Total mass = 66 g

Mole fraction methanol: 0.3

Sum of mole fraction = 1

Therefore, mole fraction of water = 0.7

Let's find out the mass of each component by this two equations:

Methanol mass + Water mass = 66 g

Water mass = 66g - Methanol mass

Methanol mass = 66g - water mass

water mass / 18 g/mol = moles of water

methanol mass / 32 g/mol = moles of methanol

moles of water / total moles = 0.7

moles of methanol / total moles = 0.3

water mass / 18 g/mol / (water mass / 18 g/mol) + (methanol mass / 32 g/mol) = 0.7 ; let's replace methanol mass, as (66 - water mass)

water mass / 18 g/mol / (water mass / 18 g/mol) + (66 - water mass / 32 g/mol) = 0.7 → The unknown is water mass (X)

X / 18 / ( (X / 18) + ((66-X) / 32)) = 0.7

(X / 18) + ((66-X) / 32) = (16X + 594 - 9X)/288

X / 18 / (16X + 594 - 9X)/288 = 0.7

X/18 = 0.7 . ( (7X + 594 ) / 288)

X / 18 = 7/2880 ( 7X + 594)

X = 7/2880 ( 7X + 594) 18

X = 7/160 (7X + 594)

X = 49/160X + 2079/80

X - 49/160X = 2079/80

111/160X = 2079/80

X = 2079/80 . 160/111 = 37.5 g → mass of water

Therefore, mass of methanol → 66 g - 37.4 g = 28.5 g

7 0

3 years ago

The decomposition of 57.0 g of Fe2O3 results in Consider the following reaction. 2Fe2O3 ---> 4Fe + 3O2 deltaH degree rxn = +

lozanna [386]

Answer:

The correct answer is option E.

Explanation:

$2Fe_2O_3\rightarrow 4Fe + 3O_2 \Delta H^o_{rxn} = 824.2 kJ$

Mass of ferric oxide decomposed = 57.0 g

Moles of ferric oxide decomposed = $\frac{57.0 g}{160 g/mol}=0.35625 mol$

According to reaction, 2 moles ferric oxide on combustion gives 824.2 kJ of heat.

Then heat given by on decomposition of 0.35625 mol of ferric oxide will be:

$\frac{824.2 kJ}{2}\times 0.35625 =146.81 kJ\approx 147 kJ$

So, on decomposition of 57.0 grams of ferric oxide 147 kilo Joules of heat was released.

3 0

3 years ago

1. An arch is a landform formed when wind picks up tiny bits of rock and sand and blows them against

Strike441 [17]

Answer:

B

Explanation:

8 0

3 years ago