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8 months ago

How do the products of chemical reactions compare to their reactants?

Chemistry

1 answer:

Ket [755]8 months ago

8 0

The products of chemical reactions often have completely different properties than the reactants, like viscosity, boiling and melting temperatures, etc.

That is because the atoms form new and different bonds to give the products.

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Land breezes near bodies of water occur because

Aleksandr [31]

B) land cools off much faster than water (creating a air region of high density above land and lower density above sea)

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3 years ago

Sometimes people do not want to change their belief regardless of the evidence.

bagirrra123 [75]

Answer:

True

Explanation:

Ex. People against vaccines tend to believe crazy theories over facts because they think they'll end up brainwashing them.

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2 years ago

How does wavelength differ in high and low frequency waves?

Taya2010 [7]

Waves with higher frequencies have shorter wavelengths, and lower frequencies have longer wavelengths

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3 years ago

Read 2 more answers

C) Mercury is solid at room temperature....True Or False<br>

Zielflug [23.3K]

Answer:

true

Explanation:

Because Mercury can be solidified when its temparature us brought to its freezing point. However, when returned to room temparature conditions, mercury does not exist in solid state for long, and returns back to its more common liquid form.

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2 years ago

The most useful ore of aluminum is bauxite, in which Al is present as hydrated oxides, Al2O3 * xH2O.

lesantik [10]

Answer:

44.7 kWh

Explanation:

Let's consider the reduction of Al₂O₃ to Al in the Bayer process.

6 e⁻ + 3 H₂O + Al₂O₃ → 2 Al + 6 OH⁻

We can establish the following relations:

The molar mass of Al is 26.98 g/mol.
2 moles of Al are produced when 6 moles of e⁻ circulate.
1 mol of e⁻ has a charge of 96468 c (Faraday's constant).
1 V = 1 J/c
1 kWh = 3.6 × 10⁶ J

When the applied electromotive force is 5.00 V, the energy required to produce 3.00 kg (3.00 × 10³ g) of aluminum is:

$3.00 \times 10^{3} gAl.\frac{1molAl}{26.98gAl} .\frac{6mole^{-}}{2molAl}.\frac{96468c}{1mole^{-}}.\frac{5.00J}{c}.\frac{1kWh}{3.6 \times 10^{6}J} =44.7kWh$

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3 years ago