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Lesechka [4]
3 years ago
13

Give an example of a time when you would want to increase friction.

Chemistry
1 answer:
Snezhnost [94]3 years ago
6 0

1) you want to increase friction when it gets cold. If you're outside and it's really cold, you're going to rub your hands to warm them up, therefore friction is increasing

I'm not do sure about decreasing.

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In a game of tug of war, team one pulls to the right with a force of 500 newtons and team two pulls to the left with a force of
SOVA2 [1]

Answer:

100 n to the right

Explanation:

6 0
2 years ago
You need to prepare a solution with a specific concentration of Na+Na+ ions; however, someone used the end of the stock solution
babymother [125]

Explanation:

Ionic equation

NaCl(aq) --> Na+(aq) + Cl-(aq)

Na2SO4(aq) --> 2Na+(aq) + SO4^2-(aq)

In NaCl solution, 1 mole of Na+ is dissociated in 1 liter of solution while in Na2SO4, 2 moles of Na+ is dissociated in 1 liter of solution.

Molecular weight of NA2SO4 = (23*2) + 32 + (16*4)

= 142 g/mol

Molecular weight of NaCl = 23 + 35.5

= 58.5 g/mol

Masses

% Mass of NA+ in Na2SO4 = mass of Na+/total mass of Na2SO4 * 100

= 46/142 * 100

= 32.4%

% Mass of NA+ in NaCl = mass of Na+/total mass of NaCl * 100

= 23/58.5 * 100

= 39.3%

Therefore, the % mass of Na+ in NaCl and Na2SO4 are different so it cannot be used.

7 0
3 years ago
select from this list the one metal or alloy that is best suited for each of the following applications, and cite at least one r
Brut [27]

<em>List of metal or alloy that is best-suited include :</em>

<em>1) Block of an </em><em>internal combustion </em><em>engine is made of grey cast </em><em>iron </em><em>because it is </em><em>ductile </em><em>and hard enough to bear the loads.</em>

<em>2) Steam heat exchanger is made up of </em><em>stainless steel </em><em>material as it has high resistance to </em><em>corrosion </em><em>and has the capacity to bear high-</em><em>temperature </em><em>differences.</em>

<em>3) For jet engine </em><em>turbofan blades</em><em>, titanium alloys are being used because they can able to bear high pressure and high energy loads.</em>

<em>4) Tool </em><em>steel </em><em>is used to make drill bit material as it has high </em><em>tensile </em><em>and point strength.</em>

<em>5) </em><em>Aluminum alloys </em><em>are used for </em><em>cryogenic </em><em>applications as it is the best suited for work at low </em><em>temperatures</em><em>.</em>

<em>6) </em><em>Magnesium </em><em>is used for </em><em>pyrotechnics </em><em>as it gives works on the effect of heat, </em><em>light</em><em>, and gas. </em>

<em />

<em />

Alloy, a metallic substance composed of two or more elements, as both a compound or a solution. The components of alloys are ordinarily themselves metals, though carbon, a nonmetal, is an essential constituent of metal.

Alloys, in trendy, are more potent and harder, less malleable, much less ductile, and greater corrosion-resistant than the alloy's predominant metallic.

An alloy is created with the aid of mixing metallic with another issue, both any other metal or a nonmetal substance. Metallic alloys are commonly made by means of melting the substances, mixing them collectively, after which letting them cool to room temperature, ensuing in a strong material.

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Learn more about Alloy here:-brainly.com/question/1759694

#SPJ4

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3 0
1 year ago
Which of the following will affect the rate of a chemical reaction?
dimulka [17.4K]

Answer:

Solute concentration will afect the rate of a chemical reaction, because you must work with molarity

Explanation:

I think that solute mass may be it can affect the rate of reaction, if you have more mass in a solute, you will also have more moles.

If you want to know more, you have to consider temperature in the reaction and the  presence of catalysts. They all, affect reactions.

7 0
3 years ago
Read 2 more answers
When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot
viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

Formula used :

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number  of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0
3 years ago
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