Answer:
6.22 × 10⁻⁵
Explanation:
Step 1: Write the dissociation reaction
HC₆H₅COO ⇄ C₆H₅COO⁻ + H⁺
Step 2: Calculate the concentration of H⁺
The pH of the solution is 2.78.
pH = -log [H⁺]
[H⁺] = antilog -pH = antilog -2.78 = 1.66 × 10⁻³ M
Step 3: Calculate the molar concentration of the benzoic acid
We will use the following expression.
Ca = mass HC₆H₅COO/molar mass HC₆H₅COO × liters of solution
Ca = 0.541 g/(122.12 g/mol) × 0.100 L = 0.0443 M
Step 4: Calculate the acid dissociation constant (Ka) for benzoic acid
We will use the following expression.
Ka = [H⁺]²/Ca
Ka = (1.66 × 10⁻³)²/0.0443 = 6.22 × 10⁻⁵
Answer:
a) 2
b) 2
c) 5
d) 5
e) 5
Explanation:
a) There is 1 Ag atom and 1 Cl atom. <em>When there's no subscript number next to an element, it means there is only one.</em>
b) There is 1 Ca atom and 1 O atom.
c) There are 3 Mg atoms (there's a subscript 3 next to Mg) and 2 N atoms.
d) There are 2 Al atoms and 3 O atoms.
e) There are 2 Sc atoms and 3 S atoms.
Answer:
Hey there!
This is already rounded to four significant figures!
Zeroes after the decimal but before the 7 don't count, and 7, 0, 6, and 2 count as significant figures.
So, the answer would be 0.007062.
Let me know if this helps :)
Explanation:
Ionic bonds
Covalent bond
Vanderwaal force of attraction
