Answer:
168.56 mL
Explanation:
density = mass/volume, use basic algebra skills to replace the volume and solve
T = 2T , P = 2P as given in the question
Volume = mass *density
Now apply ideal gas law
PV=nRT
V = nRT/P
substitute value of V and P
V = nR2T/2P
V =nRT/P
mass*density = nRT/P
density will not change
Answer:
T₂ = 218.75 K
Explanation:
Given data:
Initial volume = 20 L
Initial pressure = 16 atm
Initial temperature = 500 K
Final temperature = ?
Final volume = 35 L
Final pressure = 4 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
by putting values,
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁/ P₁V₁
T₂ = 4 atm × 35 L × 500 K / 16 atm × 20 L
T₂ = 70000 atm .L. K / 320 atm.L
T₂ = 218.75 K
<u>Ans: Mass of NaNO3 = 574 g</u>
<u>Given:</u>
Volume of NaNO3, V = 4.50 L
Molarity of NaNO3, M = 1.50 M i.e. 1.50 moles/L
Molar mass of NaNO3 = 85.00 g/mol
<u>To determine:</u>
The mass of NaNO3
<u>Explanation:</u>
Molarity of a solution can be expressed as the number of moles of the solute in a liter volume of solution
Molarity of NaNO3 = moles of NaNO3/volume of solution in L
1.50 moles/L = moles/4.50 L
moles NaNO3 = 1.50 *4.50 = 6.75 moles
Now, moles of NaNO3 = mass of NaNO3/molar mass NaNO3
mass of NaNO3 = moles * molar mass =
= 6.75 moles * 85.00 g/mole
= 573.75 g = 574 g
Sorry I’m only answering so I could upload
