1.
The energy stored in a capacitor is given by
where
C is the capacitance
V is the potential difference across the capacitor
In this problem, we have
is the capacitance of the capacitor
is the p.d. across the capacitor
Solving the equation, we find the energy stored:
2.
The average power delivered to the coils is equal to the ratio between the energy released and the time taken:
where
is the energy released by the capacitor
is the time taken
Substituting into the formula, we find
Answer:
The amount saved in a year is $ 278.6.
Explanation:
current, I = 0.275 A
Voltage, V = 120 V
cost = $ 0.20 per kWh
The energy spent in 1 year is given by
E = V I t
E = 120 x 0.275 x 365 x 24 x 3600
E = 1.04 x 10^9 J
1 kWh = 3.6 x 10^6 J
So,
E = 288.9 kWh
So, the cost is
C = $ 0.2 x 288.9 = $ 57.78
So, the amount saved = $ 336.384 - $ 57.78 = $ 278.6
Answer:
Explanation:
Given
mass of stone=0.250 kg
Let initial velocity with which it is thrown upward is u
therefore after time t it's velocity is zero at highest point
t=
where g= gravity at earth
therefore -------1
Now same thing is done in Planet X where gravity is g'
therefore time taken by stone to reach surface is
-------2
Divide 1 & 2
=
=
g'=
Answer:
<u>Box 1</u>
Explanation:
Formula we are using :
<u>Force = mass × acceleration</u>
or
<u>mass = Force / acceleration</u> (since mass needs to be found)
=============================================================
Box 1 :
⇒ mass = 5 N / 5 m/s²
⇒ mass = 1 kg
=========================================================
Box 2 :
⇒ mass = 5 N / 0.75 m/s²
⇒ mass = 5 × 4/3 = 20/3 kg
⇒ mass = 6.67 kg
===========================================================
Box 3 :
⇒ mass = 5 N / 4.3 m/s²
⇒ mass = 50/43 kg
⇒ mass = 1.16 kg
===========================================================
On comparing Box 1, Box 2, and Box 3, we understand that <u>Box 1</u> has the smallest mass
Answer:
his displacement is 772.85 ft
Explanation:
Given;
initial velocity of his jump, u = 2 ft/s
final velocity of his jump, v = - 223 ft/s
time of motion, t = 7 seconds
acceleration due to gravity, g = 32.17 ft/s²
Let downward motion = positive direction
Let his displacement after 7s = Δh
Apply the following kinematic equation to determine his displacement.
Therefore, his displacement is 772.85 ft