1.204 x 10 ( 24 ) atoms of magnesium are present.
In order to go from mass of magnesium there have to do 2 things
1. convert mass of Mg to moles of Mg using the molar mass of Mg as converted to a factor
2. convert moles of Mg to atoms of Mg using the Avogadro's number ( 6.02 x 10 (23) as a conversion factor
Hope my it helped a little :) <span />
Answer:
23 kPA
Explanation:
95kPa = 24kPA (CO2) + 48 kPa (N) + x kPa (O)
24kPA(CO2)+ 48kPA (N) = 72 kPA
95kPA - 72kPA= 23kPA (O)
Answer:
1)
2) The dependent variable = The time it takes for one pendulum swing
3) The independent variable = The length of the pendulum string with weight at the bottom
Explanation:
The relationship between the length of the pendulum string and the time it takes for one pendulum swing is giving as follows;
Where;
T = The period of oscillation = The time to complete one oscillation =Two swings of the pendulum
L = The length of the pendulum
g = The acceleration due to gravity
Therefore, the time it takes for one pendulum swing is directly proportional to the square root of the length of the pendulum
The dependent variable = The time it takes for one pendulum swing
Th independent variable = The length of the pendulum string with weight at the bottom.
<span>this is a limiting reagent problem.
first, balance the equation
4Na+ O2 ---> 2Na2O
use both the mass of Na and mass of O2 to figure out how much possible Na2O you could make.
start with Na and go to grams of Na2O
55.3 gNa x (1molNa/23.0gNa) x (2 molNa2O/4 molNa) x (62.0gNa2O/1molNa2O) = 75.5 gNa2O
do the same with O2
64.3 gO2 x (1 molO2/32.0gO2) x (2 molNa2O/1 mol O2) x (62.0gNa2O/1molNa2O) = 249.2 g Na2O
now you must pick the least amount of Na2O for the one that you actually get in the reaction. This is because you have to have both reacts still present for a reaction to occur. So after the Na runs out when it makes 75.5 gNa2O with O2, the reaction stops.
So, the mass of sodium oxide is
75.5 g</span>
Answer:
= 0.00325 moles of beryllium
Explanation:
Molarity or concentration is given by the formula;
Molarity = Number of moles/Volume in L
Therefore, to get the number of moles
Moles = Molarity × Volume
= 0.025 M × 0.13 L
<u>= 0.00325 moles of beryllium</u>
