Chemical reaction: PCl₅ → PCl₃ + Cl₂.
n(PCl₅) = 0,366 mol.
V(PCl₅) = 4,45 L.
c(PCl₅) = n(PCl₅) ÷ V(PCl₅).
c(PCl₅) = 0,366 mol ÷ 4,45 L.
c(PCl₅) = 0,082 mol/L.
Kc = 1,80.
[PCl₃] = [Cl₂] = x.
Kc = [PCl₃] · [Cl₂] ÷ [PCl₅].
1,80 = x² ÷ (0,082 mol/L - x).
Solve quadratic eqaution: x = [PCl₃] = 0,078 mol/L.
[PCl₅] = 0,082 mol/L - 0,078 mol/L.
[PCl₅] = 0,004 mol/L.
Answer:
Explanation:
Dipole moment = charge x separation of charges
= (2 x 1.6 x 10⁻¹⁹ ) x ( 140 x 10⁻¹² ) coulomb-metre
= 448 x 10⁻³¹coulomb-metre
1 debye = 3.33 x 10⁻³⁰coulomb-metre
Dipole moment in debye = 448 x10⁻³¹ / 3.33 x 10⁻³⁰debye
= 448 x10⁻³¹ / 33.3 x 10⁻³¹
= 13.45 debye
=
Answer:
Explanation:
Molar heat capacity at constant volume Cv of a gas = n x .5 R where n is degree of freedom of the gas molecules
CO₂ is a linear molecule , so number of degree of freedom = 3 + 2 = 5
3 is translational and 2 is rotational degree of freedom . There is no vibrational degree of freedom given .
So Cv = 5 / 2 R
= 2.5 R .
Answer:
ΔT = 76.5 °C
Explanation:
Given data:
Amount of water = 100.0 g
Energy needed = 32000 J
Change in temperature = ?
Solution,
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values in formula.
Q = m.c. ΔT
ΔT = Q / m.c
ΔT = 32000 j/ 100.0 g × 4.184 j/g. °C
ΔT = 32000 j / 418.4 j /°C
ΔT = 76.5 °C
