To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
thx
Step-by-step explanation:
Answer:
The answer to question 4 is 25.
Step-by-step explanation:
25 ÷ 5 = 5
"/" the slanted thing is another way of saying divide.
Answer: 14/5
Step-by-step explanation:
