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NARA [144]
3 years ago
12

7^x=4 “Identify the closest integer value to X.”

Mathematics
1 answer:
vova2212 [387]3 years ago
7 0

Answer:

X=1

Step-by-step explanation:

X is supposed to be a constant number if i understand the question right the ^ is supposed to symbolised a gap so it is 7 + ^ +1 how the question is written is not based to standard acedemic level it would rather be something like the following

2x+2≤1

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From the following figure, why can you not conclude that lines l and m are parallel?
vichka [17]

Answer:

A

Step-by-step explanation:

For the lines to be parallel then the 2 corresponding angles would have to be congruent. However, they are not , one is 120 the other is 118

Hence corresponding angles postulate are not congruent.

8 0
3 years ago
Read 2 more answers
How do i find these angles
tresset_1 [31]
1- the answer is 120

360 - (180 + 60) = 360 - 240  \\  = 120



2- the answer is 74

360 - (135 + 77) = 360 - 212  \\  = 148 \\  \\  148 \div 2 = 74




3- it's 84
42 \times 2 = 84





good luck
3 0
3 years ago
Please help!
Sergio039 [100]

Answer:

The answer could be 0 or 1 out of 4, because choosing a card at first and not putting it back, then picking a second card at random, it would likely be one in zero attempts to pick 3 again but otherwise that it could be 1 out of 4 because it could be possible picking 3 at the first try.

3 0
3 years ago
Si el gerente de control de calidad desea estimar la media de vida de lámparas con 20 horas, con un nivel de confianza del 95% y
vfiekz [6]

English translation:

If the quality control manager wants to estimate the average life of lamps with 20 hours, with a confidence level of 95% and an error of 10% is assumed. What is the sample size?

6 0
3 years ago
If an initial amount A0 of money is invested at an interest rate i compounded times a year, the value of the investment after t
seropon [69]

Answer:

Following are the solution to the given point:

Step-by-step explanation:

Please find the comp[lete question in the attached file.

Given:

\bold{ \lim_{n \to \ \infty} (1+ \frac{r}{n})^{nt} =e^{rt}}

In point 1:

\to y = (1+ \frac{r}{n})^{nt}

In point 2:

\to \ln (y)= nt \ln(1+  \frac{r}{n})

In point 3:

Its key thing to understand, which would be that you consider the limit n to\infty,  in which r and t were constants!  

=lim_{n \to \ \infty}  \ln (y) =  lim_{n \to \ \infty}  nt \ln(1+\frac{r}{n})\\\\=  lim_{n \to \ \infty} \frac{\ln(1+\frac{r}{n})}{\frac{1}{nt}}\\\\=  lim_{n \to \ \infty} \frac{\frac{-r}{\frac{n^2}{(1+\frac{r}{n})}}}{- \frac{1}{n^2t}}\\\\=  lim_{n \to \ \infty} \frac{\frac{rn^2t}{n^2}}{(1+\frac{r}{n})}\\\\=  lim_{n \to \ \infty} \frac{rt}{(1+\frac{r}{n})}\\\\= \frac{rt}{(1+\frac{r}{0})}\\\\=rt

In point 4:

\to \lim_{n \to \ \infty} = (1+\frac{r}{n})^{nt} and

\to \lim_{n \to \ \infty} = A_0e^{rt}

7 0
3 years ago
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