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RSB [31]
3 years ago
11

Write the equation of the line that is perpendicular to y=2x-7 and passes through the point (6, 5)

Mathematics
2 answers:
lapo4ka [179]3 years ago
7 0

ANSWER:

Perpendicular means the slopes are negative-reciprocals.

So, the slope of the new line is the negative-reciprocal of 2 i.e, - 1/2.

Using point-slope,

y - 5 = - 1/2(x - 6)

y = - 1/2 x + 3 + 5

y = - 1/2x + 8.

So, <u>Correct choice</u> - [B] y = - 1/2x + 8.

Pani-rosa [81]3 years ago
3 0

Answer:

B

Step-by-step explanation:

we are given a equation of a line

we want to figure out the equation of the perpendicular line passes through the <u>(</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u>points

in order to do so

recall that,

\displaystyle m_{ \text{perpendicular}} =   - \frac{1}{m}

we got from our given equation that m=2

because equation of a line is y=mx+b

thus

\displaystyle m_{ \text{perpendicular}} =   - \frac{1}{2}

remember that, when we want to figure out perpendicular line or parallel line we should the formula given by

\displaystyle y -  y_{1} = m(x -  x_{1})

since we got our perpendicular m is -½, x_1=6 and y_1=5, substitute

\displaystyle y -  5 =   - \frac{1}{2} (x -  6)

to get the perpendicular equation you should simplify the above equation to y=mx+b form

distribute -½:

\displaystyle y -  5 =   - \frac{1}{2} x  + 3

add 5 to both sides:

\displaystyle y  =   - \frac{1}{2} x  + 8

hence,

our answer choice is B

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