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Anni [7]
2 years ago
9

How much bigger is the area of a circle with a radius of 5 cm than a circle with a radius of 3 cm?

Mathematics
1 answer:
Deffense [45]2 years ago
6 0

<u>Given:</u><u> </u>

  • Circle with radius 5cm and 3 cm

<u>To </u><u>Find</u><u>:</u><u> </u>

  • How much bigger is the area of a circle.

<u>Solution:</u>

Area of circle with Radius 5cm

Area of circle = πr²

Area of circle = 22/7 × 5 × 5

Area of circle = 22/7 × 25

Area of circle = <u>78.54 </u><u>cm</u><u>²</u>

Now,

Area of circle with Radius 3 cm

Area of circle = 22/7 × 3 × 3

Area of circle = 22/7 × 9

Area of circle = <u>28.27 cm²</u>

= 78.54 - 28.27

= 50.27cm

Hence,

  • <u>Area of circle is 50.27</u><u>c</u><u>m</u><u> more than that area of circle with radius 3cm</u>
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V+8w=4v,for v<br><br> -m+5n=-2, for n
jok3333 [9.3K]

Answer:

  • v = 8w/3,
  • n = (m - 2)/5.

---------------------------

<h3>Given equations</h3>
  • v + 8w = 4v and - m + 5n = - 2

<h3>Solve the first equation for v</h3>
  • v + 8w = 4v
  • 4v - v = 8w
  • 3v = 8w
  • v = 8w/3

<h3>Solve the second equation for n</h3>
  • - m + 5n = - 2
  • 5n = m - 2
  • n = (m - 2)/5
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1 year ago
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Rena's rowboat drifts 23 feet from shore,
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2 years ago
What is the area of this composite figure?<br>A. 135 cm2<br>B. 207 cm2<br>C. 249 cm2<br>D. 279 cm2
mariarad [96]

Answer:

249 cm^2

Step-by-step explanation:

This problem becomes easier if we subdivide the figure, find the areas of the resulting figures and then sum them up.

Draw a vertical line straight down from the edge marked "4 cm" towards the edge marked "18 cm."  The resulting rectangle on the left is 15.5 cm long and (18 - 7.5) cm wide, or 15.5 by 10.5 cm.  Its area is 162.75 cm^2.

Next, find the area of the rectangle on the right of the line we drew.  Its width is 7.5 cm and its height (15.5 - 4) cm, resulting in an area of 86.25 cm^2.

Last, add together these two subareas:  combine 86.25 cm^2 and 162.75 cm^2.  The total area of the composite figure is then 249 cm^2 (answer).

7 0
3 years ago
what is the volume of a oblique cylinder with the height of 6 cm and a 4 cm as the radius of its base
JulsSmile [24]

Answer :

  • 301.44 cm³

⠀

Explanation :

We know,

{ \longrightarrow \qquad\pmb {\boldsymbol{ Volume_{(cylinder)} = \pi {r}^{2} h \: }}}

Where,

  • <em>r</em> is the radius of the cylinder. Here, the radius is 4 cm

  • <em>h</em> is the height of the cylinder. Here, height is 6 cm

  • Here, we will take the value of π as 3.14 approximately .

⠀

Substituting the values in the formula :

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times ({4})^{2} \times 6 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times 16\times 6 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times 96 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \it{ \pmb{ Volume_{(cylinder)}  {= 301.44 \: }}}}}}

⠀

Therefore,

  • The volume of the cylinder is 301.44 cm³ approximately.
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2 years ago
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Help I have a lot to do
BaLLatris [955]
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(intro) Slope is change in y divided by change in x (axes). Here, the y axis is depth and the x axis is hours. So, the slope is change in depth between any two points, divided by the change in hours between the same points. The slope of this line is half a foot depth divided by 2 hours.
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b) The graph shows a constant rate of change because the line is straight (it increases at the same speed. If the line was curving, it would not be a constant rate of change).
c) Yes, because the line has a constant rate of change now.
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