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Anni [7]
2 years ago
9

How much bigger is the area of a circle with a radius of 5 cm than a circle with a radius of 3 cm?

Mathematics
1 answer:
Deffense [45]2 years ago
6 0

<u>Given:</u><u> </u>

  • Circle with radius 5cm and 3 cm

<u>To </u><u>Find</u><u>:</u><u> </u>

  • How much bigger is the area of a circle.

<u>Solution:</u>

Area of circle with Radius 5cm

Area of circle = πr²

Area of circle = 22/7 × 5 × 5

Area of circle = 22/7 × 25

Area of circle = <u>78.54 </u><u>cm</u><u>²</u>

Now,

Area of circle with Radius 3 cm

Area of circle = 22/7 × 3 × 3

Area of circle = 22/7 × 9

Area of circle = <u>28.27 cm²</u>

= 78.54 - 28.27

= 50.27cm

Hence,

  • <u>Area of circle is 50.27</u><u>c</u><u>m</u><u> more than that area of circle with radius 3cm</u>
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23, 24 And 25 please. Thank you!
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Step-by-step explanation:

23. area of rect,r = 11 x 3.5 = 38.5cmsq

area of tri, t = 6 x3.5/2 = 10.5 cmsq

area of shaded region, sr = r-t

=> sr = 38.5- 10.5 = 28.5cmsq

24. area of square, s = 10x10 = 100mmsq

area of circle, c = pi x 5^2 = 78.5mmsq

area of shaded region, sr = s - c

=> sr = 100- 78.5 = 22.5mmsq

25. area of circle, c = pi x 6^2 = 113.04insq

area of tri, t = 6x12/2 = 36insq

area of shaded region, sr = c - t

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3 years ago
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Two equations given. We have to find the solution sets for the equations.

y = -x²-2x+8 and y = 2x +11

There are 3 steps given. As both equations are equal to y, so we can equate the x parts.

-x²-2x+8 = 2x+11

0 = x²+4x+3

0 = (x+1)(x+3)

Now we have to use zero product property to solve this. If multiplication of two terms equal to 0, we can set each of them equal to 0.

x+1 = 0 , x+3 = 0

When, x+1 =0, by moving 1 to the other side we will get x = -1.

When x+3 =0, by moving 3 to the other side we will get x =-3

Now for the two values of x, we have to find y .

When x = -1, by plugging in the value to the second equation we will get,

y = 2x+11 = 2×(-1)+11 = -2 +11 = 9

So for x =-1, y =9.

The solution set is (-1, 9)

Now when x = -3, by plugging in the value to the second equation we will get,

y = 2x+11 = 2×(-3) +11 = -6+11 = 5

So for x = -3, y = 5

The solution set is (-3,5)

Therefore, the solutions for the system of equations are (-3, 5) and (-1, 9)

So the third option is correct.

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